Convert character vector to evaluable expression
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I have a similar problem to this: Convert cell array of character vectors to evaluable expressions - (mathworks.com)
However, the elements in my cell array are not numerical expressions, but rather variables and struct paths. I tried using sscanf using %f, %d, or %s as formatSpecs. The first 2 returns empty arrays and the latter just returns the original character vector. This is what I am doing.
struct.field1.subfield = 5;
vec = {'struct.field1.subfield'};
sscanf(vec{1},'%s')
I want to get 5.
采纳的回答
S.field1.subfield = 5; % do NOT use STRUCT as a variable name.
vec = 'S.field1.subfield';
spl = split(vec,'.');
val = getfield(S,spl{2:end})
Good data design avoids dynamically accessing the variable name (S in the above example):
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