Adjusting plot fill to show two colours depending on overestimation/underestimation
1 次查看(过去 30 天)
显示 更早的评论
Hello,
I have the following code to plot my observed readings versus my modelled readings and the code works fine but does not clearly show regions where my modelled data is greater than observed data.
% Create figure
figure1 = figure;
XData = mod1_2001_2014(x,1)';
YData1 = mod1_2001_2014(x,5)';
YData2 = mod1_2001_2014(x,4)';
% Plot with fill
X = [XData fliplr(XData)];
Y = [YData1 fliplr(YData2)];
fill(X,Y,[0.678431391716003 0.921568632125854 1]);
ylim([0 max(YData2)+3])
I was wondering if there is a way to have this so that when the YData2 > YData1 the fill is red and when YData1 > YData2, the fill is the colour it is now.
Any ideas? Thank you!
0 个评论
采纳的回答
Thorsten
2014-11-27
编辑:Thorsten
2015-2-5
or my solution that does need no interpolation but computes the intersection points.
function fillline(x, y1, y2, col1, col2)
% Thorsten Hansen 2015-05-02 2014-11-27
% See also
% http://www.mathworks.com/matlabcentral/fileexchange/34876--greater-than--fill
if nargin < 3
x = -10:10;
y1 = sin(x);
y2 = cos(x);
end
if nargin < 5
col1 = [1 0 0];
col2 = [0 0 1];
end
hold on
colpatch(y1 >= y2, col1, x, y1, y2)
colpatch(y2 >= y1, col2, x, y1, y2)
plot(x, y1, '-', 'Color', col1)
plot(x, y2, '-', 'Color', col2)
hold off
function colpatch(ind, col, x, y1, y2)
% special case 1: all values of y2 below y1: nothing to fill
if ~any(ind)
return
end
% define fill color as a lighter version of the color on the line above
col = lighten(col);
% force row vectors for proper concatenation in fill below
x = x(:)'; y1 = y1(:)'; y2 = y2(:)'; ind = ind(:)';
% special case 2: no intersections, all values of y2 above y1
if all(ind)
fill([x x(end) fliplr(x) x(1)], ...
[y1 y1(end) fliplr(y2) y2(1)], col, 'EdgeColor', col);
return
end
% general case: y1 and y2 intersect
val = cumsum(diff([0 ind]) == 1).*ind;
v = 1;
ind = find(val == v);
while ~isempty(ind)
xi = x(ind); y1i = y1(ind); y2i = y2(ind);
% determine intersections to fill area between intersections
% determine left intercept
ii = ind(1);
if ii > 1
line1 = [x(ii) y1(ii); x(ii-1) y1(ii-1)];
line2 = [x(ii) y2(ii); x(ii-1) y2(ii-1)];
[xis_left yis_left] = lineintercept(line1, line2);
else
xis_left = [];
yis_left = [];
end
% determine right intercept
ii = ind(end);
if ii < numel(x)
line1 = [x(ii) y1(ii); x(ii+1) y1(ii+1)];
line2 = [x(ii) y2(ii); x(ii+1) y2(ii+1)];
[xis_right yis_right] = lineintercept(line1, line2);
else
xis_right = [];
yis_right = [];
end
% add patch
fill([xis_left xi xis_right fliplr(xi)], ...
[yis_left y1i yis_right fliplr(y2i)], col, 'EdgeColor', col);
%set(h), pause
v = v + 1; % next patch
ind = find(val == v); % indices of next patch
end
function [xis yis] = lineintercept(line1, line2)
slope = @(line) (line(2,2) - line(1,2))/(line(2,1) - line(1,1));
m1 = slope(line1);
m2 = slope(line2);
intercept = @(line,m) line(1,2) - m*line(1,1);
b1 = intercept(line1,m1);
b2 = intercept(line2,m2);
% intersection
xis = (b2-b1)/(m1-m2);
yis = m1*xis + b1;
%plot(xis,yis,'ko','MarkerSize',10)
function col = lighten(col)
col = col + 0.8*([1 1 1] - col);
6 个评论
Thorsten
2015-2-5
Hi Masao,
I missed to also force "ind" to be a row vector. Please find the updated fillline function above. Hope this works now smoothly for everything :-)
Best,
Thorsten
更多回答(1 个)
Luuk van Oosten
2014-11-27
Dear Massao,
I do not know exactly how your data looks like, but you could use somthing like:
for i=1:lenght(yourdataset)
if YData1 < YData2 % Let matlab check if Ydata2 is larger than YData1
scatter( x(i,1), y(i,5), 15, [1 0 0], 'filled') hold on;
else % if this condition is not matched, then do the following:
scatter( x(i,1), y(i,4),15, [0 0.68 0.92], 'filled') hold on;
end
Have fun!
3 个评论
Luuk van Oosten
2014-11-27
Oops, excuse me. I'm not very familiar with plotting lines.
nevertheless, if you try something analogous to
if Ydata1 < Ydata2
fill stuff in fancy blue
else
fill stuff in red
I would expect that to work.
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Discrete Data Plots 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!