What does this array operation do?

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I have two 2D square arrays of the same size, array1 and array 2. What does this operation do?
x = array1(array2)

采纳的回答

Image Analyst
Image Analyst 2022-2-8
If array2 is a logical (binary) array then it takes those elements from array1 that are 1 in array2.
For example
array1 = magic(5)
array1 = 5×5
17 24 1 8 15 23 5 7 14 16 4 6 13 20 22 10 12 19 21 3 11 18 25 2 9
array2 = false(5);
array2(2, 3) = true;
array2(3, 1) = true
array2 = 5×5 logical array
0 0 0 0 0 0 0 1 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0
x = array1(array2) % This will be a vector, not a 2-D array.
x = 2×1
4 7
So see how it took the (3,1) and (2,3) element and strung them together into a vector?
On the other hand if the array2 is an integer array, it will use those as linear indexes into the array 1.
The linear indexes are in column major order (down rows first, them move across columns):
1 6 11 16 21
2 7 12 17 22
3 8 13 18 23
4 9 14 19 24
5 10 15 20 25
So if array 2 was
array2 = [2, 7; 17,22]
array2 = 2×2
2 7 17 22
x = array1(array2)
x = 2×2
23 5 14 16
It will take those elements from row 2 that had those linear indexes.

更多回答(1 个)

KSSV
KSSV 2022-2-8
  1. If array2 is double and have fractions it will throw error.
  2. If array2 is logical i.e. it has 0 and 1's. It will give elements of array1 where array2 is 1.
  3. If array2 has all integers, it will give the respective elements. As array2 acts like indecing.

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