Moving Average with timestep

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MakM
MakM 2022-2-8
编辑： Jan 2022-2-9
I have an array M=[1,4,7,6,4.5,7.5,8.5,4.5] and for time t=[1,2,3,4,5,6,7,8]. I have to find the average of M w.r.t t, with a window size of 2 and step size of window should be 1 or 2. How can I do that?
I am using movmean function to calculate the average, how can I used the window and the step size in this function?
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Jan
Jan 2022-2-9
Yes, this is what was suggested yesterday.
If the length of M is a multiple of 2, an equivalent code is:
v = (M(1:2:end) + M(2:2:end)) * 0.5;
t = t(1:2:end)
MakM
MakM 2022-2-9
Thank you Jan, Kindly paste your answer, so I can accept :)

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Jan
Jan 2022-2-9
编辑：Jan 2022-2-9
A simple average over 2 elements (length of M can be even or odd):
Len = numel(M);
v = (M(1:2:Len - rem(Len, 2)) + M(2:2:Len)) * 0.5;
t = t(1:2:end)

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