Error graphing a VVF

2 次查看(过去 30 天)
I am trying to graph this VVF but it saying "Expected input to be one of these types: function_handle, sym Instead its type was double." What am I doing wrong?
syms t
x = (exp(-t))*sin(t)
y = (exp(-t))*cos(t)
z = 1
fplot3(x, y, z, [0, pi])

采纳的回答

Star Strider
Star Strider 2022-2-9
The ‘z’ function needs to be defined as symbolic. Without that provision, fplot3 sees it as a double, not a symbolic constant (which is what you want it to see).
Add that ...
syms t
x = (exp(-t))*sin(t)
x = 
y = (exp(-t))*cos(t)
y = 
z = sym(1)
z = 
1
fplot3(x, y, z, [0, pi])
... to get what I assume is the desired result.
.
  2 个评论
Cassandra Meyer
Cassandra Meyer 2022-2-9
Yes, this is perfect. Thank you so much!
Star Strider
Star Strider 2022-2-9
As always, my pleasure!

请先登录,再进行评论。

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Number Theory 的更多信息

产品


版本

R2021b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by