Unable to use a value of type graph as an index.

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Omer Iqbal
Omer Iqbal 2022-2-10
评论： Cris LaPierre 2022-2-10
Hi!
I am getting the error in below codes. I have all the inputs in workspace but I am still getting this error. Can anybody help me to resolve this error? Please find the screeshot of an error in an attachment.
for i=1:m
current_node = neigh_nodes_deg_2(i,1);
preceding_node = origin_node;
edge_path = [origin_node;current_node];
counter = 1;
% note: if the graph contains a closed sub-graph, the while loop will
% not end. Stop, identify the loop and correct it within the
% shapefile
while isempty(neigh_nodes_deg_2(G2,current_node,preceding_node))~=1
succeeding_node = niegh_nodes_deg_2(G2,current_node,preceding_node);
preceding_node = current_node;
current_node = succeeding_node;
edge_path = [edge_path; current_node];
counter = counter + 1;
end

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回答（1 个）

Cris LaPierre
Cris LaPierre 2022-2-10
Your variable G2 is a graph obejct, but you are using it to index the first position (rows) of neigh_nodes_deg_2, which is a vector.
% vv Here
while isempty(neigh_nodes_deg_2(G2,current_node,preceding_node))~=1
  2 个评论
Omer Iqbal
Omer Iqbal 2022-2-10
Hi!
Thanks for your suggestions. Did you mean to change the order of variable is the solution? For instance, see below;
while isempty(neigh_nodes_deg_2(current_node,G2, preceding_node))~=1
However, it is still giving me an error by re arrangment of variables.
Cris LaPierre
Cris LaPierre 2022-2-10
Ran in:
You cannot use G2 as an index at all, It is not the value you think it is. Here is an example of the error.
A=1:3;
p=plot(A);
% your error
A(p)
Unable to use a value of type matlab.graphics.chart.primitive.Line as an index.

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