sum logical 1's independently for each column

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Michael Angeles 2022-2-11

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回答： Michael Angeles 2022-2-14

采纳的回答： DGM

logical data count .xlsx

I've attached a sample data from excel.

how can I create a "for loop" to sum each column and give me print out total for each column.

I also need to compare the "length" of the column to the sum of the logical 1's in that column then print out a pass or fail for each column tested.

example:

1 1 1 1

1 1 1 0

1 1 1 1

-----------sum

first column = 4 ==length(column) = pass

fourth column = 3 == lenght(column = fail

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DGM 2022-2-12

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编辑：DGM 2022-2-13

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If the inputs are integer-valued, just use all()

A = randi([0 1],5)
A = 5×5
     0     0     1     1     0
     1     1     1     1     0
     1     0     0     1     1
     0     0     0     1     0
     0     0     0     1     1
isfull = all(A,1)
isfull = 1×5 logical array
   0   0   0   1   0
% if you really need text output for some reason
flmap = {'fail','pass'};
fulllabels = flmap(isfull+1)
fulllabels = 1×5 cell array
    {'fail'}    {'fail'}    {'fail'}    {'pass'}    {'fail'}

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Michael Angeles 2022-2-13

Thanks DGM, I will try this one if it fits the output that we are looking for.

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David Hill 2022-2-12

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No loop is needed.

r=readmatrix('logicalDataCount.xlsx');
s=sum(r);
l=s==size(r,1);

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David Hill 2022-2-13

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The below code is completely flexible (does not depend on the size of r)

s=sum(r);
allPassed = (numPasses == size(r, 1));

You are really not understanding, the logical array above tells you every column that is passed (1) or failed (0). Converting the logical array to 'pass' or 'fail' is trivial.

Michael Angeles 2022-2-13

Hi David,

Thanks...Maybe I don't understand...The reason why I want each column to print out pass or fail as part of the output message is to inform the operator immediately that the column checked for a certain message passed or failed. This allows the operator to re-run the test.

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Michael Angeles 2022-2-14