non zero elements in an array

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ali hassan
ali hassan 2022-2-12
编辑： Matt J 2022-2-13
if a=[1 2 4 5 3 0 0 8 0]
how can i make the elements greater than or equal to 2 as 1 and smaller than two as 0.
so that it become like this:
[0 1 1 1 1 0 0 1 0]

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采纳的回答

Arif Hoq
Arif Hoq 2022-2-12
Ran in:
a=[1 2 4 5 3 0 0 8 0];
[idx]=find(a<2);
a(idx)=0;
out=a;
[idx2]=find(out>=2);
out(idx2)=1
out = 1×9
0 1 1 1 1 0 0 1 0
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ali hassan
ali hassan 2022-2-13
@DGM@Arif Hoq@Catalytic in haste, i made a mistake.
i have rectified it. i am sorry for it.
i intended to ask the same what @Arif Hoq replied. though in my question, i wrote zero instead of two but i got the concept which was required.
Matt J
Matt J 2022-2-13
编辑：Matt J 2022-2-13
Ran in:
but i got the concept which was required.
Except that this solution still teaches the regrettably popular habit of using find() in situations where it is unnecessary.
a=[1 2 4 5 3 0 0 8 0];
out=a;
out(a<2)=0;
out(a>=2)=1
out = 1×9
0 1 1 1 1 0 0 1 0

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更多回答（2 个）

DGM
DGM 2022-2-12
编辑：DGM 2022-2-12
Ran in:
I'm going to assume you're only dealing in integers here, otherwise the question arises whether values between 1 and 2 should really be preserved.
a = [1.5 1 2 4 5 3 0 0 8 0];
b = max(min(a,1),0)
b = 1×10
1 1 1 1 1 1 0 0 1 0
If values between 1 and 2 should be preserved, then:
c = max(a,0);
c(c>=2) = 1
c = 1×10
1.5000 1.0000 1.0000 1.0000 1.0000 1.0000 0 0 1.0000 0
Matt J
Matt J 2022-2-12
编辑：Matt J 2022-2-13
Ran in:
If a are always integers,
a = [1 2 4 5 3 0 0 8 0];
a=(a>=2)
a = 1×9 logical array
0 1 1 1 1 0 0 1 0

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