How can i modify this code so x can = 0
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function qw=fNR(x)
qw=zeros(100,1)
qw(2)=x
i=2
while abs(qw(i)-qw(i-1))>1e-6
qw(i+1)=qw(i)-ff1(qw(i))/fdf1(qw(i))
i=i+1
end
qw=qw(2:i-1)
[qw(end) i]
plot(qw)
end
how can i model this functio so it can take fNR(0)
fdf1
function y=fdf1(x)
y=3*x.^2-12*x+11;
end
ff1
function y=ff1(x)
y=x.^3-6*x.^2+11*x-5;
end
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回答(1 个)
Image Analyst
2022-2-12
Try this:
function qw=fNR(x)
qw=zeros(100,1)
qw(2)=x
i=2
maxIterations = 1000;
loopCounter = 0;
while (abs(qw(i)-qw(i-1))>1e-6) && loopCounter < maxIterations
qw(i+1)=qw(i)-ff1(qw(i))/fdf1(qw(i))
i=i+1
loopCounter = loopCounter + 1;
end
qw=qw(2:i-1)
if isempty(qw)
message = sprintf('qw is empty')
uiwait(warndlg(message));
return;
end
[qw(end) i]
plot(qw)
end
5 个评论
Image Analyst
2022-2-13
@Muhammad Choudhury I know that was your error with the original code. Obviously you never ran my code because my code throws up an alert that the array is empty rather than your error.
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