How to get Points(x,y) from function

2022 2 13
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更新时间：2022 2 15
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hi everybody,
how can i get X,Y values from the following matlab-script?
X = @(t) 0.5 + 0.5*(((abs(cos(t))).^B)/cos(t))
Y = @(t) 0.5*T*(((abs(sin(t))).^B)/sin(t))*(1 - (0.5 + 0.5*(((abs(cos(t))).^B)/cos(t))).^P) + C*sin(((0.5 + 0.5*(((abs(cos(t))).^B)/cos(t))).^E * pi)) + R*sin((0.5 + 0.5*(((abs(cos(t))).^B)/cos(t)))*2*pi)
t = [0.01:0.01:2*pi]
B = 1.75
T = 0.18
P = 1.1
C = 0.11
E = 0.8
R = 0.0
fplot(X,Y)
As you can see in the attaches photo, I couldn't have then. I just could plot them

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Voss
Voss 2022-2-13
Ran in:

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Ran in:
t = [0.01:0.01:2*pi]
t = 1×628
0.0100 0.0200 0.0300 0.0400 0.0500 0.0600 0.0700 0.0800 0.0900 0.1000 0.1100 0.1200 0.1300 0.1400 0.1500 0.1600 0.1700 0.1800 0.1900 0.2000 0.2100 0.2200 0.2300 0.2400 0.2500 0.2600 0.2700 0.2800 0.2900 0.3000
B = 1.75
B = 1.7500
T = 0.18
T = 0.1800
P = 1.1
P = 1.1000
C = 0.11
C = 0.1100
E = 0.8
E = 0.8000
R = 0.0
R = 0
X = @(t) 0.5 + 0.5*(((abs(cos(t))).^B)./cos(t))
X = function_handle with value:
@(t)0.5+0.5*(((abs(cos(t))).^B)./cos(t))
Y = @(t) 0.5*T*(((abs(sin(t))).^B)./sin(t)).*(1 - (0.5 + 0.5*(((abs(cos(t))).^B)./cos(t))).^P) + C*sin(((0.5 + 0.5*(((abs(cos(t))).^B)./cos(t))).^E * pi)) + R*sin((0.5 + 0.5*(((abs(cos(t))).^B)./cos(t)))*2*pi)
Y = function_handle with value:
@(t)0.5*T*(((abs(sin(t))).^B)./sin(t)).*(1-(0.5+0.5*(((abs(cos(t))).^B)./cos(t))).^P)+C*sin(((0.5+0.5*(((abs(cos(t))).^B)./cos(t))).^E*pi))+R*sin((0.5+0.5*(((abs(cos(t))).^B)./cos(t)))*2*pi)
fplot(X,Y)
X = X(t)
X = 1×628
1.0000 0.9999 0.9998 0.9997 0.9995 0.9993 0.9991 0.9988 0.9985 0.9981 0.9977 0.9973 0.9968 0.9963 0.9958 0.9952 0.9946 0.9939 0.9932 0.9925 0.9917 0.9909 0.9901 0.9892 0.9883 0.9873 0.9864 0.9853 0.9843 0.9832
Y = Y(t)
Y = 1×628
0.0000 0.0000 0.0000 0.0001 0.0001 0.0002 0.0003 0.0003 0.0004 0.0006 0.0007 0.0008 0.0009 0.0011 0.0013 0.0014 0.0016 0.0018 0.0021 0.0023 0.0025 0.0028 0.0031 0.0033 0.0036 0.0040 0.0043 0.0046 0.0050 0.0053

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