I don't know what's wrong with the function.

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채원 이 2022-2-14

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https://ww2.mathworks.cn/matlabcentral/answers/1649280-i-don-t-know-what-s-wrong-with-the-function

评论： Walter Roberson 2022-2-14

It is a function consisting of t, Q, and C. I was trying to express this in MATLAB. But a problem arose in expressing Q. But I don't know why it's a problem. The red part seems to be wrong, but I can't fix it.

function dCdt = name(t,C,dz,u_column,D,F,H)
dCdt = zeros(column_Number*(Nz+1),1);
dQdt = name2(t,Q,C,H,Nz,column_Number)
C(1)=0.2;
for k = 1 : 4
    for i = 1 : 100
        dCdz(i) = 1./(dz).*(C(i)-C(i-1)); 
        d2Cdz2(i) = 1./(dz^2.).*(C(i)-2.*C(i-1)+C(i-2)); 
        % dQdt(i) = H*dCdt(i);
        dCdt(i) = D.*d2Cdz2(i) - u_column*dCdz(i) + F*dQdt(i);
    end % for i = 1 : 100
end % for k = 1 : 4
end % function
function dQdt = name2(t,Q,C,H)
for k = 1 : 4
    for i = 1 : 100
        Q(i) = H*C(i);
        dQdt(i) = H*dCdt(i);
    end % for i = 1 : 100
end % for k = 1 : 4
end % function

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VBBV 2022-2-14

put a snapshot of error ( in red color text)

Walter Roberson 2022-2-14

在 MATLAB Online 中打开

for k = 1 : 4
    for i = 1 : 100
        Q(i) = H*C(i);
        dQdt(i) = H*dCdt(i);
    end % for i = 1 : 100
end % for k = 1 : 4

The assignments index at i but k is not used inside the nested loop. The exact same thing is going to be done every iteration of the for k loop -- the output is going to be exactly the same as if you did not have any for k loop.

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