An integer multiple a function

I want the code run with 5 different graph on loop. But the result is just one. Can anyone help me please?
load ecg_hw2.mat;
n = [4:0.01:4];
N = [2 4 8 16 32];
b = 1./N;
ye = cell(size(b));
t = 1/200;
T2 = 0:t:1000;
h = dirac(n);
idx = h == Inf;
h(idx) = 1;
for i = numel(b);
ye{i} = b(i)*(conv(ecg,h));
figure (4);
subplot(6,1,i);
plot(ye{i});
end

 采纳的回答

n isn't defined. I'm assuming that's T2?
load ecg_hw2.mat;
N = [2 4 8 16 32];
b = 1./N;
ye = cell(size(b));
t = 1/200;
T2 = 0:t:1000;
h = dirac(T2);
idx = h == Inf;
h(idx) = 1;
for i = 1:numel(b)
ye{i} = b(i)*(conv(ecg,h));
%figure(4);
subplot(5,1,i);
plot(ye{i});
end

1 个评论

My code is exactly like you, but my result just show up 1 graph. I dont know why, can you hep me plese?

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更多回答(1 个)

I dont know the value of n. I took it 200.
A=load('ecg_hw2.mat');
ecg=A.ecg ;
N = [2 4 8 16 32];
b = 1./N;
ye = cell(size(b));
t = 1/200;
T2 = 0:t:1000;
n = [4:0.01:4];
h = dirac(n);
idx = h == Inf;
h(idx) = 1;
for i = 1:numel(b);
ye{i} = b(i)*(conv(ecg,h));
figure (4);
subplot(3,2,i);
plot(ye{i})
end

3 个评论

My code is exactly like you, but I dont know why I have 1 graph on figure, it must be 5 plots. Can you help me please?
Arif Hoq
Arif Hoq 2022-2-15
编辑:Arif Hoq 2022-2-15
in your code you forgot to start indexing from 1(look at herein your code: for i = numel(b)). that's why you are getting a single plot i guess.You need a range of indices. I have updated the code.
I really appreciate you. I cant believe I forget very basic matlab

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