Create a permutation of elements in the same position

N=3;
x=rand(1,N); y=rand(1,N); z=rand(1,N);
A=zeros(N^3,3); %initialize array
for i=1:N
    for j=1:N
        for k=1:N
            A(N^2*(i-1)+N*(j-1)+k,:)=[x(i),y(j),z(k)];
        end
    end
end

Try it. Good luck.

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Answer 2

Yongjian Feng 2022-2-15

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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1650240-create-a-permutation-of-elements-in-the-same-position#answer_896550

Just 3 for loops.

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Answer 3

DGM 2022-2-15

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链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1650240-create-a-permutation-of-elements-in-the-same-position#answer_896570

编辑：DGM 2022-2-15

在 MATLAB Online 中打开

Consider the example:

% input coordinates
x = [1 2]; 
y = [11 22];
z = [111 222];
% create the index array
m = (dec2bin(0:7,3) == '1') + 1;
% all combinations in order
xyz = [x(m(:,1)); y(m(:,2)); z(m(:,3))].'
xyz = 8×3
     1    11   111
     1    11   222
     1    22   111
     1    22   222
     2    11   111
     2    11   222
     2    22   111
     2    22   222

Or more generally:

x = [1 2 3]; 
y = [11 22 33];
z = [111 222 333];
% create the index array
nx = numel(x);
m = repmat((1:nx)',[nx*2 1]);
m = [repelem(m(1:size(m,1)/nx,1),nx) m];
m = [repelem(m(1:size(m,1)/nx,1),nx) m];
% get the combinations like before
xyz = [x(m(:,1)); y(m(:,2)); z(m(:,3))].'
xyz = 18×3
     1    11   111
     1    11   222
     1    11   333
     1    22   111
     1    22   222
     1    22   333
     1    33   111
     1    33   222
     1    33   333
     2    11   111