how to calculate the value from function define

1 次查看（过去 30 天）

shiv gaur 2022-2-16

评论： Walter Roberson 2022-2-16

la0 = 650; k0 = 2*%pi/la0; ef = 1; ec = -19.6224-0.443*%i; es=ec;

pc = ef/ec; ps = ef/es;

bcinf = sqrt(ec*ef/(ec+ef));

tol = 1e-12;

acut = -real(1/pc/sqrt(ef-ec))/k0;

wc = 2*acut;

nc = sqrt(ef);

w = 5:10:3500; //% thickness range for TM0

w1 = 1.001*wc:10:3500; //% thickness range for TM1

function be=f(la0, ef, ec, w, bcinf, m, tol);

for j=1:length(w)

be(j) = f(la0,ef,ec,w(j),bcinf,0,tol);

end

for j=1:length(w1)

be1(j) = f(la0,ef,ec,w1(j),bcinf,1,tol);

end

neff0 = real(be0); L0 = -1/2./imag(be0)/k0/1000; //% TM0 index & distance

neff1 = real(be1); L1 = -1/2./imag(be1)/k0/1000;// % TM1 index & distance

w2=1000; a = w2/2;// % specific solutions

b = f(la0,ef,ec,a,bcinf,0,tol);// % TM0

p = f(la0,ef,ec,a,bcinf,1,tol);// % TM1

neff02 = real(be02); L02 = -1/2/imag(be02)/k0/1000;

end

disp(be,b,p)

pl help to solve the problem to disp(be,b,p)

Walter Roberson 2022-2-16

Your function f calls itself multiple times, and does so unconditionally. That is an infinite loop.

在 Help Center 和 File Exchange 中查找有关 Number Theory 的更多信息

R2021b

Find the treasures in MATLAB Central and discover how the community can help you!

Translated by