for loop only gives me one value
显示 更早的评论
hello, i'm trying to write this code, however when I calculate xi it keep giving me one value, even though both alpha_g and ki_1 has 6 values. which then stops me from calculating yi with the following error
Index exceeds the number of array elements (1).
Error in Module_b (line 44)
yi(i)=xi(i).*ki_1(i);
this is the code:
for i=1:nc
if (min<alpha_g(i)&&alpha_g(i)<max)
for i=1:nc
xi(i)= z1./(1+alpha_g(i).*(ki_1(i)-1));
for i=1:nc
yi(i)=xi(i).*ki_1(i);
end
end
elseif alpha_g>=1
yi=z1;
else
xi=z1;
end
end
采纳的回答
David Hill
2022-2-16
Only one loop is needed.
for m=1:nc %don't use the same indexing variable (you are already inside a loop)
xi(m)= z1./(1+alpha_g(m).*(ki_1(m)-1));
yi(m)=xi(m).*ki_1(m);
end
更多回答（1 个）
Torsten
2022-2-16
You only set xi(1) in
for i=1:nc
xi(i)= z1./(1+alpha_g(i).*(ki_1(i)-1));
but refer to xi(1) up to xi(6) in the following loop
for i=1:nc
yi(i)=xi(i).*ki_1(i);
end
Furthermore, since there are nested loops in your code fragment, you cannot use the same loop index "i" every time.
2 个评论
Eyad Alkhotani
2022-2-16
Torsten
2022-2-16
For this, you have to close the first for-loop:
for i=1:nc
xi(i)= z1./(1+alpha_g(i).*(ki_1(i)-1));
end
for i=1:nc
yi(i)=xi(i).*ki_1(i);
end
or simply
for i=1:nc
xi(i)= z1./(1+alpha_g(i).*(ki_1(i)-1));
yi(i)= xi(i).*ki_1(i);
end
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