find the absolute path of a package

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Daniel
Daniel 2014-12-3
评论： Daniel 2014-12-3
Hi!
is there an obvious way to find out the absolute path of a package? I mean, if I define a package directory some where in my file system, say,
mkdir <mypath>/+myPackage
and the add its location to the path
addpath <mypath>
then myPackage is active and I can invoke functions from there. But how can I ask the system where this package resides? I mean
which myPackage
does not work. I could make a which to a function inside the myPackage, yes, but I have hundreds of packages, and packages inside packages, and they don't contain the same functions.
any idea? Daniel

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Guillaume
Guillaume 2014-12-3
编辑：Guillaume 2014-12-3
It's the what function you want:
s = what('event'); %there may be several packages with the same name. s may be an array of structs
s.path
You can also get a lot of information from the meta.package classes (but not the path unfortunately):
mpack = meta.package.fromName('event')
allpackages = meta.package.getAllPackages
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Daniel
Daniel 2014-12-3
exactly! Thanks, Guillaume! The output is a little confusing (I get an arrays of structs, one for the absolute path of the package and one for the relative path!), but I'm closer to goal now. This meta.xxx objects are really useful, and I keep forgetting they exist!

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更多回答（1 个）

Image Analyst
Image Analyst 2014-12-3
If you know the name of one of the m-files in the package, then you can do this:
% Determine folder where someFunction.m lives.
folder = fileparts(which('someFunction.m'));
  1 个评论
Daniel
Daniel 2014-12-3
The problem is that I have lots of packages, and cannot predict in advance the name of a function garanteed to be inside a given package.

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