how to plot the equation

12 次查看（过去 30 天）
shiv gaur
shiv gaur 2022-2-21
评论： Image Analyst 2022-2-21
x(0)=1;
y(0)=0
t=1:15;
for n=1:15
x(n+1)=(x(n-1)-y(n))/n+1;
y(n+1)=(x(n)+y(n)-t)/n+1
plot(t,x)
end
  2 个评论
shiv gaur
shiv gaur 2022-2-21
x(0) is the initial value you take as x0
Image Analyst
Image Analyst 2022-2-21
Yeah, I figured that, but what I meant by my answer below is you're supposed to do
x(1) = 1;
y(1) = 0;

请先登录，再进行评论。

请先登录，再回答此问题。

采纳的回答

Image Analyst
Image Analyst 2022-2-21
编辑：Image Analyst 2022-2-21
Indexing starts at 1, not 0. Also, check your formulas - they look weird.
For example in
y(n+1)=(x(n)+y(n)-t)/n+1
you need t(n), not just t which is the entire array.
y(n+1)=(x(n)+y(n)-t(n))/n+1
  4 个评论
显示 2更早的评论
Image Analyst
Image Analyst 2022-2-21
Ran in:
OK, so it's all working now that you're starting your vectors at index 1 instead of 0, and changed t to t(n)? If so, can you accept this answer because I pointed out the problems? If not, post your current code so we can continue to work on it. This is what I got. Let me know if it's the same as what you have.
x = zeros(1, 16);
y = zeros(1, 16);
x(1)=1;
% y(1)=0
t=1:15;
for n = 2: length(x) - 1
fprintf('n = %d.\n', n);
x(n+1) = (x(n-1)-y(n)) / n + 1; % Note only n is in the denominator, not (n+1)
y(n+1) = (x(n)+y(n)-t(n)) / n + 1;
end
n = 2. n = 3. n = 4. n = 5. n = 6. n = 7. n = 8. n = 9. n = 10. n = 11. n = 12. n = 13. n = 14. n = 15.
plot(t, x(1:end-1), 'b.-', 'LineWidth', 2, 'MarkerSize', 30);
hold on;
plot(t, y(1:end-1), 'r.-', 'LineWidth', 2, 'MarkerSize', 30);
grid on;
xlabel('t', 'FontSize', 20);
ylabel('x or y', 'FontSize', 20);
title('x or y VS. t', 'FontSize', 20);
legend('x', 'y')

请先登录，再进行评论。

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Matrix Indexing 的更多信息

标签

产品


版本

R2021b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by