How can I apply a logical mask to an image variable?

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dila suay
dila suay 2022-2-24
评论： Kaitlin Wang 2022-2-24
Hello,
I am trying to apply a logical mask to an image variable, however I couldnt manage to do it so far.
I have tried
maskedRgbImage = bsxfun(@times, rgbImage, cast(mask, 'like', rgbImage));
maskedRgbImage = rgbImage.*mask
Also, I've tried to apply mask to the rgbImage.CData directly. All of them are giving me errors. What else I can try?
Thank you so much
  2 个评论
Walter Roberson
Walter Roberson 2022-2-24
Your rgbImage is a handle to a deleted image() object -- not an array of data.
dila suay
dila suay 2022-2-24
Hi Walter, thank you for your quick reply. I uploaded a .fig version. I hope it is useful

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采纳的回答

Walter Roberson
Walter Roberson 2022-2-24
rgb = rgbImage.CData;
maskedImage = rgb .* cast(repmat(c, [1 1 size(rgb,3)]),'like',rgb);
This cannot be an image() object unless you want to do something like
maskedRgbImage = copyobj(rgbImage, gca);
rgb = rgbImage.CData;
maskedImage.CData = rgb .* cast(repmat(c, [1 1 size(rgb,3)]),'like',rgb);
... but that would be directly on top of the old image.
  2 个评论
dila suay
dila suay 2022-2-24
Thank you so much for your quick replies Walter. It says
Unrecognized function or variable 'c'.
What is c?
Walter Roberson
Walter Roberson 2022-2-24
rgb = rgbImage.CData;
maskedImage = rgb .* cast(repmat(mask, [1 1 size(rgb,3)]),'like',rgb);
or
maskedRgbImage = copyobj(rgbImage, gca);
rgb = rgbImage.CData;
maskedImage.CData = rgb .* cast(repmat(mask, [1 1 size(rgb,3)]),'like',rgb);

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更多回答（1 个）

Image Analyst
Image Analyst 2022-2-24
You don't need to do both of these:
maskedRgbImage = bsxfun(@times, rgbImage, cast(mask, 'like', rgbImage));
maskedRgbImage = rgbImage.*mask
All you need is the first one. Don't do the second one. It's not right and would need "fixing".
  1 个评论
Kaitlin Wang
Kaitlin Wang 2022-2-24
sir you are my hero. i have been looking at your answers for weeks and learning so much. thank you

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