sin graph plot in reverse time

2022 2 26
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更新时间：2022 2 26
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if we take the value of t from 1 to 100 then plot is ok but we take the value of time in reverse then plot is not able
wrong size is showing is there any method to take value in reverse to plot for example
t=100:1
t=zeros(100.1)
y=zeros(100.1)
for i=100:1
y(i)=sin(t(i))
plot(t,y)
end
plot is not showing

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 采纳的回答

Arif Hoq
Arif Hoq 2022-2-26
Ran in:

0 个投票

Ran in:
i think you don't need a loop here
t=100:-1:1;
y=sin(t);
plot(t,y)

4 个评论
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shiv gaur
shiv gaur 2022-2-26
why value on x axis forom 1 to 100 we want the value from 100 to 1
Arif Hoq
Arif Hoq 2022-2-26
just put this line
set(gca,'XDir','reverse')
Arif Hoq
Arif Hoq 2022-2-26
Ran in:
Ran in:
you need to x axis direction in reverse
t=100:-1:1;
y=sin(t);
plot(t,y)
set(gca, 'XDir','reverse')
shiv gaur
shiv gaur 2022-2-26
you are req to apply this in this equation
sigma = 10;beta = 8/3;rho = 28;f = @(t,a) [-sigma*a(1) + sigma*a(2); rho*a(1) - a(2) - a(1)*a(3); -beta*a(3) + a(1)*a(2)];[t,a] = ode45(f,[0 100],[1 1 1]); plot3(a(:,1),a(:,2),a(:,3))
set(gca,'XDir','reverse')

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