sin graph plot in reverse time

2 次查看(过去 30 天)
if we take the value of t from 1 to 100 then plot is ok but we take the value of time in reverse then plot is not able
wrong size is showing is there any method to take value in reverse to plot for example
t=100:1
t=zeros(100.1)
y=zeros(100.1)
for i=100:1
y(i)=sin(t(i))
plot(t,y)
end
plot is not showing

采纳的回答

Arif Hoq
Arif Hoq 2022-2-26
i think you don't need a loop here
t=100:-1:1;
y=sin(t);
plot(t,y)
  4 个评论
Arif Hoq
Arif Hoq 2022-2-26
you need to x axis direction in reverse
t=100:-1:1;
y=sin(t);
plot(t,y)
set(gca, 'XDir','reverse')
shiv gaur
shiv gaur 2022-2-26
you are req to apply this in this equation
sigma = 10;beta = 8/3;rho = 28;f = @(t,a) [-sigma*a(1) + sigma*a(2); rho*a(1) - a(2) - a(1)*a(3); -beta*a(3) + a(1)*a(2)];[t,a] = ode45(f,[0 100],[1 1 1]); plot3(a(:,1),a(:,2),a(:,3))
set(gca,'XDir','reverse')

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