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How to remove repeated values mantaining the first one from an array ?

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I have something like:
10000111111111011011100000111011000111111011000000010101011111111....
how to:
00000100000000010010000000100010000100000010000000000000010000000....
The second repetition makes the beggining of a series.

回答(2 个)

Sean de Wolski
Sean de Wolski 2014-12-8
abs(diff('0000111001111101101'))
  1 个评论
Guillaume
Guillaume 2014-12-8
Hum, it looks like the OP only wants the transitions from 0 to 1 (which would be diff(x) > 0) but only when there's more than one consecutive 1 (which is not as simple unfortunately).

Guillaume
Guillaume 2014-12-8
s = '10000111111111011011100000111011000111111011000000010101011111111'
o = char('0' + ([0 diff(s) > 0] & [~diff(s) 0]))

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