shift matrix to the right

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Nimasha Pilippange
Nimasha Pilippange 2022-2-26
评论： Nimasha Pilippange 2022-2-28
Hello,
I need to compare 2 matrices. One is 1x1280 and other is 1x5120. So I need to take the 1st one to the other range. How do i do that.
for example: A=[0 0 1 1 0 0 1 1], B=[0 0 0 0 1 1 1 1 0 0 0 0 1 1 1 1]. The number of elements in B is an integer multiple of number of elements in A. After shifting I need to subtract A by B.
Any Idea?
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Nimasha Pilippange
Nimasha Pilippange 2022-2-27
Yes I think we need scaling too. Once I get both the data in one range I need to susbstrat one from another. I attached the images again. Let me know if there is any more detail you need.
Image Analyst
Image Analyst 2022-2-27
You forgot to answer my question. Which is it: 1 or 2?

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Image Analyst
Image Analyst 2022-2-27
Ran in:
Try this:
markerSize = 30;
% Say a goes from 250 to 4800 and has 60 elements
a = 250 + (4800-250) * rand(1, 60);
% Say b goes from 100 to 900 and has 30 elements
b = 100 + (900-100) * rand(1, 30);
plot(a, 'b.-', 'LineWidth', 2, 'MarkerSize', markerSize);
hold on;
plot(b, 'c.-', 'LineWidth', 2, 'MarkerSize', markerSize);
grid on;
% Rescale b so that it also goes from 250 to 4800
b = rescale(b, min(a), max(a));
% Interpolate b so that it has the same number of elements as a.
bq = linspace(1, length(b), length(a));
b2 = interp1(b, bq);
plot(b2, 'r.-', 'LineWidth', 2, 'MarkerSize', markerSize);
% Find differences
c1 = a - b2;
c2 = b2 - a;
legend('a', 'b', 'b2')

更多回答（3 个）

Scott MacKenzie
Scott MacKenzie 2022-2-26
编辑：Scott MacKenzie 2022-2-26
Ran in:
Perhaps this is what you are looking for:
A=[0 0 1 1 0 0 1 1]
A = 1×8
0 0 1 1 0 0 1 1
B=[0 0 0 0 1 1 1 1 0 0 0 0 1 1 1 1]
B = 1×16
0 0 0 0 1 1 1 1 0 0 0 0 1 1 1 1
m = numel(A);
n = numel(B);
Anew(n-m+1:n) = A % shifted to match B with zeros at beginning
Anew = 1×16
0 0 0 0 0 0 0 0 0 0 1 1 0 0 1 1
Image Analyst
Image Analyst 2022-2-26
It appears no one knows what you mean since it's not clearly explained and you didn't give the resulting difference vector. So here is another guess:
A=[0 0 1 1 0 0 1 1];
B=[0 0 0 0 1 1 1 1 0 0 0 0 1 1 1 1];
% Resize smaller vector to be the same size as the larger vector.
a2 = imresize(A, size(B), 'nearest')
% "subtract A by B" - whatever that means. Here are two possibilities
c = a2 - B
c = B - a2
Let me know if either of these is what you want.
Voss
Voss 2022-2-27
Ran in:
Maybe use interp1() (or resample()):
nx = 20;
x = randn(1,nx);
% xr = resample(x,4,1);
xr = interp1(1:nx,x,1:0.25:nx);
figure();
plot(1:nx,x,'-o');
hold on
plot(0.25*(4:numel(xr)+3),xr,'.');
legend({'Original','Interpolated x4'})

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