Timeit on pause(2) returns weird ouput

2022 2 28
1 个回答
更新时间：2022 3 2
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0 个投票

I am trying to get the timeit function to work.I read https://uk.mathworks.com/help/matlab/ref/timeit.html and get the example:
X = rand(100);
f = @() svd(X);
t1 = timeit(f)
I want to try this using the pause(2), since this should take about 2 seconds:
g = @() pause(2);
t2 = timeit(g)
the output is
t2 =
3.4639e-06
which is a lot less than the expected 2 seconds. Clearly I am missunderstanding something (which probably makes my more serious attempts at using timeit also wrong), but what?

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回答（1 个）

Peter Perkins
Peter Perkins 2022-3-2

0 个投票

The issue is pause, not timeit:
"STATE = pause(...) returns the state of pause previous to processing the input arguments."
>> t2 = timeit(g,0)
t2 =
2.000208413333

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