How to index a cell array of character vectors?

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Ludovico Nati
Ludovico Nati 2022-2-28
编辑： Voss 2022-3-1
Hello everyone,
I have problem in my code. Suppose I have 'c' which is a cell array of character vectors of dimension N by 1. I would like to index each element of 'c' with a given pair of 'si' (start index) and 'ei' (end index), which can be different for any element of 'c'. 'si' and 'ei' are both N by 1 numerical vector or cell array containg numerical elements.
I would like a function to use in cellfun like in this piece of code: newc = cellfun(@tbd,c,si,ei,'UniformOutput',false). 'newc' of course is a new cell array of character vectors , where the ith element would be like: newc{i} = x{i}(si{i}:ei{i});
I can create a function tbd (to be determined) by myself but I think that there are already more efficient and native way to do it.
Thanks for your help!

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Voss
Voss 2022-3-1
编辑：Voss 2022-3-1
Ran in:
% If si and ei are cell arrays containing scalar indices:
c = {'indexing'; 'a cell array'; 'of character'; 'vectors'};
si = {1; 3; 4; 5};
ei = {5; 6; 7; 6};
newc = cellfun(@(x,y,z)x(y:z),c,si,ei,'UniformOutput',false)
newc = 4×1 cell array
{'index'} {'cell' } {'char' } {'or' }
% If si and ei are numeric vectors:
c = {'indexing'; 'a cell array'; 'of character'; 'vectors'};
si = [1; 3; 4; 5];
ei = [5; 6; 7; 6];
newc = arrayfun(@(x,y,z)x{1}(y:z),c,si,ei,'UniformOutput',false)
newc = 4×1 cell array
{'index'} {'cell' } {'char' } {'or' }
% or:
newc = cellfun(@(x,y,z)x(y:z),c,num2cell(si),num2cell(ei),'UniformOutput',false)
newc = 4×1 cell array
{'index'} {'cell' } {'char' } {'or' }
  2 个评论
Stephen23
Stephen23 2022-3-1
Why create cell array and transpose?:
si = {1,3,4,5}.';
get rid of the superfluous transpose:
si = {1;3;4;5};

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