Optimization of manipulating an array
1 次查看(过去 30 天)
显示 更早的评论
I have an array, where 0s are between non-zeros integer or floating numbers.
>> a = [1, 0, 5, 0, 6, 0, 12, 0];
I am looking to find the average of every adjacent two numbers and insert it to replace the zero between them:
like for the example above:
>> b = [1, 3, 5, 5.5, 6, 9, 12, 15]
For the last 0, we should add the difference between 12 and 9 to the last value, which is 12. So that makes (12 - 9) + 12.
I am looking for an optimized code (may be if possible without loop).
Thanks
0 个评论
采纳的回答
Ive J
2022-2-28
a = [1, 0, 5, 0, 6, 0, 12, 0];
b = a;
a_adj_mean = movmean(a(1:2:end), 2);
zero_idx = a == 0;
b(zero_idx(1:end - 1)) = a_adj_mean(2: end);
b(end) = 2*b(end-1) - b(end - 2)
更多回答(0 个)
另请参阅
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!