transform vector in 2 dimensions into one in 3
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for i = 1:duration
traci.simulation.step();
for n = 1: length(inductionID)
veicoliOGNIISTANTEsuInduction(n,i)=traci.inductionloop.getLastStepVehicleNumber(inductionID{n});
end
for v=1:length(k)
if i==t(v)
for n = 1: length(inductionID)
veicoliT(n,v)=sum(veicoliOGNIISTANTEsuInduction(n,(t(v)-(T-1)):t(v)));
end
newgreentime(:,v)=L*veicoliT(:,v); % L is a constant matrix
end
end
hi all, i have a vector n rows by v (whose columns are indexed). my vector newgreentime (:, v) in the considered v becomes a vector 4 x1, I would like to use this vector in a 3 dimensional vector 2x2xv how can I do it?
采纳的回答
Walter Roberson
2022-3-1
newgreentime(:,:,v) = reshape(L*veicoliT(:,v), 2, 2); % L is a constant matrix
This assumes that you want the order
A B C D ->
[A C
B D]
if you need
[A B
C D]
then
newgreentime(:,:,v) = reshape(L*veicoliT(:,v), 2, 2).'; % L is a constant matrix
4 个评论
Marco Carapellese
2022-3-1
You have a vector of 4 elements. Compare
v = [1;2;3;4]
reshape(v,2,2)
reshape(v,2,2).'
If you want adjacent elements in the vector to form columns, then do not use the .' but if you want adjacent elements in the vector to form rows, then you need the .' operator.
The .' operator is formally known as transpose:
transpose(reshape(v,2,2))
In general, if you have a vector v and you want to form an A by B matrix out of it, your choices are
reshape(v, A, B) %go down the columns
reshape(v, B, A).' %go across the rows
Marco Carapellese
2022-3-2
Voss
2022-3-2
" .' " (dot single-quote) is transpose.
" ' " (single-quote) is complex conjugate transpose.
If the thing you are transposing (say X) contains only real values (i.e., no complex numbers), then X.' is the same as X'
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