The OR statement "|" is not working

2022 3 3
1 个回答
更新时间：2022 3 3
4 次查看（30 天）

0 个投票

I'm trying to make the program skip that last segment if any of those numbers are the active roll value, but when the roll value is equal to one of them, it still goes through.
n = input('How many rolls: ');
count = 0;
lose = 0;
win = 0;
pointlose = 0;
pointwin = 0;
while n > count
roll = randi([2 12]);
count = count + 1;
if roll == 7
fprintf('Win\n')
win = win + 1;
count = count + 1;
elseif roll == 11
fprintf('Win\n')
win = win + 1;
count = count + 1;
elseif roll == 2
fprintf('Lose\n')
lose = lose + 1;
count = count + 1;
elseif roll == 3
fprintf('Lose\n')
lose = lose + 1;
count = count + 1;
elseif roll == 12
fprintf('Lose\n')
lose = lose + 1;
count = count + 1;
end
if roll ~= 2 | 3 | 7 | 11 | 12
point = roll;
while roll ~= point
roll = randi([2 12]);
if roll == point
fprintf('point win\n')
pointwin = pointwin + 1;
elseif roll == 7
fprintf('point loss\n')
break
end
end
else
end
end

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回答（1 个）

KSSV
KSSV 2022-3-3

1 个投票

You may consider replacing the line
roll ~= 2 | 3 | 7 | 11 | 12
with
~ismember(roll,[2 3 7 11 12])

3 个评论
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William Day
William Day 2022-3-3
编辑：William Day 2022-3-3
Doing that creates a pause at
while roll ~= point
KSSV
KSSV 2022-3-3
MAy be it is not a pause......the while loop has gone infinite.. ?
William Day
William Day 2022-3-3
编辑：William Day 2022-3-3
When I try to step through it it makes a new ismember page with things like:
if nargin == 3 && isstring(flag1)
flag1 = convertFlag(flag1);
if nargout < 2
lia = ismember(A, B, flag1);
else
[lia, locb] = ismember(A, B, flag1);
end
return
end
if nargin == 4 && (isstring(flag1) || isstring(flag2))
if isstring(flag1)
flag1 = convertFlag(flag1);
end
if isstring(flag2)
flag2 = convertFlag(flag2);
end
if nargout < 2
lia = ismember(A, B, flag1, flag2);
else
[lia, locb] = ismember(A, B, flag1, flag2);
end
return
end
And there are hundreds of lines
Perhaps because ismember is used for arrays instead of scaning for integers?

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