how to find out the time interval between two consecutive events?

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trailokya 2014-12-13

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编辑： Guillaume 2014-12-14

sir, i need to find out the time interval between two consecutive events. i have around 4000 data with increasing numbers but not consecutive. i have to find out the events of 4 consecutive numbers or more and the gap between two consecutive events. how is it possible?

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Guillaume 2014-12-14

编辑：Guillaume 2014-12-14

I've turned this question into a cody problem.

So far, the best solution is more or less the same as mine below

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Answer 1

Guillaume 2014-12-13

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https://ww2.mathworks.cn/matlabcentral/answers/166508-how-to-find-out-the-time-interval-between-two-consecutive-events#answer_162261

在 MATLAB Online 中打开

This would work:

A = [1,2,5,6,7,8,9,20,21,22,30,31,32,33, 34,35, 40,41,42,43,44];
runs = diff(A) == 1; %which numbers are part of a run
edges = diff([0 runs 0]); %find edges of run (1 = start, -1 = end)
startruns = find(edges == 1); %get indices of start of runs == indices in A 
endruns = find(edges == -1); %get indices of end of runs == indices in A
lengthruns = endruns - startruns; %get lengths of runs 
startruns = startruns(lengthruns >= 4); %only keep runs of 4 or more
endruns = endruns(lengthruns >= 4); %only keep runs of 4 or more
groupdiff = A(startruns(2:end)) - A(endruns(1:end-1))

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trailokya 2014-12-13

thank you :)

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Answer 2

dpb 2014-12-13

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https://ww2.mathworks.cn/matlabcentral/answers/166508-how-to-find-out-the-time-interval-between-two-consecutive-events#answer_162254

Check out

http://www.mathworks.com/matlabcentral/fileexchange/24255-consecutive-vector-spliter

http://www.mathworks.com/matlabcentral/fileexchange/5658-contiguous-start-and-stop-indices-for-contiguous-runs

Those are two I recall from File Exchange, there may be others as well suited to your particular problem...

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dpb 2014-12-13

在 MATLAB Online 中打开

Did you not look at the linked-to File Exchange routines? I believe either of them will do the job for you...

Without extensive testing, I believe

>> d=find(diff([0 A])>1);
>> d(diff(d)>3)
ans =
   3    11
>>

are the locations in question, but I suspect the two submittals are more robust.

trailokya 2014-12-13

the first group is 5,6,7,8,9 and the second one is 30,31,32,33,34,35 and the third one is 40,41,42,43,44 and the gap between the first and second is 21 and the second and third is 5. how it is 3 and 11?

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