how to read text file into formatted array

2 次查看（过去 30 天）
H D
H D 2014-12-15
评论： H D 2014-12-15
Hi
I have a text file which contains many rows of this shape
'0862;1;10/09/2002;09:15:59;23.845089;38.018470;486253.80;4207588.10'
I need to read each line in different cells. each cell contains data between ";" and the third and forth one are date and time while others are double numbers.
would you please help me to do so
  2 个评论
per isakson
per isakson 2014-12-15
编辑：per isakson 2014-12-15
"I need to read each line in different cells" &nbsp Why is that? And what does it exactly mean?
H D
H D 2014-12-15
thanks for comment. I need to read the whole txt file in a matrix. I presented the first line as a sample. each cell data is separated using semicolon as mentioned. in this case third and forth are date and time of day and all the rest can be saved as double in a matrix.

请先登录，再进行评论。

请先登录，再回答此问题。

采纳的回答

per isakson
per isakson 2014-12-15
编辑：per isakson 2014-12-15
Here is a function, which does what I believe is what you want. The third column of out is a serial date number.
>> out = cssm('cssm.txt')
out =
1.0e+06 *
0.0009 0.0000 0.7315 0.0000 0.0000 0.4863 4.2076
0.0009 0.0000 0.7315 0.0000 0.0000 0.4863 4.2076
0.0009 0.0000 0.7315 0.0000 0.0000 0.4863 4.2076
>> datestr( out(:,3), 31 )
ans =
2002-10-09 09:15:59
2002-10-09 09:15:59
2002-10-09 09:15:59
where
function out = cssm( filespec )
fid = fopen( filespec );
cac = textscan( fid, '%f%f%s%s%f%f%f%f' ...
, 'Delimiter',';', 'CollectOutput',true );
fclose( fid );
str = cell2mat(cac{2});
sdn = datenum( str, 'mm/dd/yyyyHH:MM:SS');
out = cat( 2, cac{1}, sdn, cac{3} );
end
and where cssm.txt contains
0862;1;10/09/2002;09:15:59;23.845089;38.018470;486253.80;4207588.10
0862;1;10/09/2002;09:15:59;23.845089;38.018470;486253.80;4207588.10
0862;1;10/09/2002;09:15:59;23.845089;38.018470;486253.80;4207588.10
  4 个评论
显示 2更早的评论
per isakson
per isakson 2014-12-15
编辑：per isakson 2014-12-15
cssm is the function defined after the word, where, in my answer.
H D
H D 2014-12-15
:D sorry for my crazy question. you are right. It works perfectly. thanks

请先登录，再进行评论。

更多回答（1 个）

Azzi Abdelmalek
Azzi Abdelmalek 2014-12-15
编辑：Azzi Abdelmalek 2014-12-15
fid=fopen('FileName.txt')
tline = fgetl(fid)
out=[];
while ischar(tline)
out{end+1,1} =tline
tline= fgetl(fid);
end
fclose(fid)
%You can aadd
A=regexp(out,';','split')
n=numel((A{1}))
B=reshape([A{:}],n,[])'
res=[cell

类别

在 Help Center 和 File Exchange 中查找有关 Large Files and Big Data 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by