How to plot wave function for finite square well? [Physics question]

11 次查看（过去 30 天）
Niklas Kurz
Niklas Kurz 2022-3-10
评论： Star Strider 2022-3-13
A question addressed to other physicist among the MATLAB community:
Considering a finite sqaure well potential:
It turns out for this certain potential a symmetric wave function can be found that fits inside
Whit constants and with the energy Eof the particle and usual physical constants.
In addition the energy has to be quantised acording to as well as
Now when I atempt plotting the piecewise wave function I don't really get continous pieces:
Ce = 1.6e-19;
scale = 1e-10;
L = 2*scale;
m = 9.109*1e-31;
h = 1.05*1e-34;
V = 100*Ce;
syms k
k = vpasolve(k*tan(L/2*k) == sqrt(2*m/h^2*V-k^2),k);
beta = k*tan(L/2*k);
dx = 0.01*scale; n = 2; x1 = -L/2*n:dx:-L/2; x2 = -L/2:dx:L/2; x3 = L/2:dx:L/2*n;
C = 1; A = 1;
psi1 = C*exp(beta*x1); psi2 = A*cos(k.*x2); psi3 = C*exp(-beta*x3);
plot(x1,psi1); hold on; plot(x2,psi2); hold on; plot(x3,psi3)
I don't right know if I messed up the physics or the code itself.
  2 个评论
Niklas Kurz
Niklas Kurz 2022-3-13
Yea, I'm also confused. In the notes I studies it was said amplitude is off importance (only for normalisation) however I do think it does matter as well.

请先登录，再进行评论。

请先登录，再回答此问题。

采纳的回答

Star Strider
Star Strider 2022-3-11
Ran in:
I do not know what it supposed to look like, however to get a continuous plot, horizongally concatenate the respectrive row vectors —
Ce = 1.6e-19;
scale = 1e-10;
L = 2*scale;
m = 9.109*1e-31;
h = 1.05*1e-34;
V = 100*Ce;
syms k
k = vpasolve(k*tan(L/2*k) == sqrt(2*m/h^2*V-k^2),k);
beta = k*tan(L/2*k);
dx = 0.01*scale; n = 2; x1 = -L/2*n:dx:-L/2; x2 = -L/2:dx:L/2; x3 = L/2:dx:L/2*n;
C = 1; A = 1;
psi1 = C*exp(beta*x1); psi2 = A*cos(k.*x2); psi3 = C*exp(-beta*x3);
plot(x1,psi1); hold on; plot(x2,psi2); hold on; plot(x3,psi3)
figure
plot([x1,x2,x3], [psi1,psi2,psi3])
grid
.

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Exploration and Visualization 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by