How to add, multiply and subtract two matrices have different length ?

32 次查看（过去 30 天）
omar th
omar th 2022-3-13
回答： Image Analyst 2022-3-26
If I have matrix A =[2 2 1; 1 2 5; 1 2 3], B=[1 2; 1 1],
How can I add or subtract these matrices while they have different length ?
  1 个评论
Torsten
Torsten 2022-3-13
Mathematical, there are no such operations for matrices of different sizes.
So you first will have to explain us how you intend to define these "additions and subtractions".

请先登录，再进行评论。

请先登录，再回答此问题。

采纳的回答

Star Strider
Star Strider 2022-3-13
Ran in:
While adding two matrices of different dimensions is not defined mathematically, it is possible to add or subtract them by indexing into them, however it is first necessary to define what elements are to be affected in the larger matrix.
Here is one approach —
A = [2 2 1; 1 2 5; 1 2 3]
A = 3×3
2 2 1 1 2 5 1 2 3
B = [1 2; 1 1]
B = 2×2
1 2 1 1
idx = 1:numel(B); % Using The Most Obvious Index Vector ...
C = A;
C(idx) = A(idx) + B(idx)
C = 3×3
3 3 1 2 2 5 3 2 3
idx = randperm(numel(A), numel(B)) % Using A Different, Random, Index Vector ...
idx = 1×4
4 6 5 1
C = A;
C(idx) = A(idx) + B(1:numel(B))
C = 3×3
3 3 1 1 4 5 1 3 3
So in a limited sense it is possible, however I have no way of knowing if either of these produces the desired result.
.
  8 个评论
显示 6更早的评论
Star Strider
Star Strider 2022-3-26
Ran in:
@omar th —
That depends on what the desired results are.
A = randi(9,3)
A = 3×3
1 2 1 3 7 3 6 2 4
B = randi(9,2)
B = 2×2
9 4 6 9
C = A;
C(1:2,1:2) = A(1:2,1:2) + B
C = 3×3
10 6 1 9 16 3 6 2 4
.
Image Analyst
Image Analyst 2022-3-26
@omar th you forgot to read Community Guidelines or these posting guidelines:
TUTORIAL: How to ask a question (on Answers) and get a fast answer
So, because of that you forgot to state what the desired results are! I guess you also missed Star's gentle hint. So, what are they? What elements get subtracted from what elements, and what elements are ignored during the operation?

请先登录，再进行评论。

更多回答（1 个）

Image Analyst
Image Analyst 2022-3-26
Perhaps this is what you want -- to subtract the upper left parts that overlap.
A = [2 2 1; 1 2 5; 1 2 3]
B = [1 2; 1 1]
[rowsA, colsA] = size(A)
[rowsB, colsB] = size(B)
maxRow = max([rowsA, rowsB])
maxCol = max([colsA, colsB])
% Pad dimensions if nexessary
if rowsA > rowsB
B(maxRow, end) = 0;
[rowsB, colsB] = size(B) % Update size
elseif rowsB > rowsA
A(maxRow, end) = 0;
[rowsA, colsA] = size(A) % Update size
end
if colsA > colsB
B(end, maxCol) = 0;
[rowsB, colsB] = size(B) % Update size
elseif colsB > colsA
A(end, maxCol) = 0;
[rowsA, colsA] = size(A) % Update size
end
% Let's see what they are now:
A
B
% Now do the subtraction of the upper left overlapping parts.
C = A - B
You get:
A =
2 2 1
1 2 5
1 2 3
B =
1 2 0
1 1 0
0 0 0
C =
1 0 1
0 1 5
1 2 3

类别

在 Help Center 和 File Exchange 中查找有关 Loops and Conditional Statements 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by