Why am i getting length(x) as 11 instead of 16?

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john
john 2022-3-13
回答： Image Analyst 2022-3-13
n=0:15;

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回答（2 个）

Torsten
Torsten 2022-3-13
If you display
length(x1)
the answer should be 16.
Image Analyst
Image Analyst 2022-3-13
Ran in:
What did you define for x? All we see are definitions for n and x1:
n=0:15;
% Compute x1
x1 = 1 .* (n >= 1) & (n <= 10)
x1 = 1×16 logical array
0 1 1 1 1 1 1 1 1 1 1 0 0 0 0 0
x1Length = length(x1) % Display it's length.
x1Length = 16
% Now define some x - a different variable than x1
x = [1,2,3,4] % Or whatever it might be.
x = 1×4
1 2 3 4
xLength = length(x) % Display it's length.
xLength = 4
I bet you had an x hanging around from a prior run and didn't call "clear all" so when you did length(x) you were getting some x that was still in the base workspace even though it was not in your script. Calling clear all would clear all old variables and prevent a problem like that.

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