Why am i getting length(x) as 11 instead of 16?

1 次查看（过去 30 天）
john
john 2022-3-13
回答： Image Analyst 2022-3-13
n=0:15;

请先登录，再回答此问题。

回答（2 个）

Torsten
Torsten 2022-3-13
If you display
length(x1)
the answer should be 16.
Image Analyst
Image Analyst 2022-3-13
Ran in:
What did you define for x? All we see are definitions for n and x1:
n=0:15;
% Compute x1
x1 = 1 .* (n >= 1) & (n <= 10)
x1 = 1×16 logical array
0 1 1 1 1 1 1 1 1 1 1 0 0 0 0 0
x1Length = length(x1) % Display it's length.
x1Length = 16
% Now define some x - a different variable than x1
x = [1,2,3,4] % Or whatever it might be.
x = 1×4
1 2 3 4
xLength = length(x) % Display it's length.
xLength = 4
I bet you had an x hanging around from a prior run and didn't call "clear all" so when you did length(x) you were getting some x that was still in the base workspace even though it was not in your script. Calling clear all would clear all old variables and prevent a problem like that.

类别

在 Help Center 和 File Exchange 中查找有关 Logical 的更多信息

标签

产品


版本

R2021b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by