Finding the functionality for the loop

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Amy Topaz 2022-3-14

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1670859-finding-the-functionality-for-the-loop

评论： Amy Topaz 2022-3-14

I am new to Matlab. I am making a formula/syntax book as a part of my club activity. I was finding logics for implementing loops in matlab without actually using loops. Is there any other way?

Is there any other way of writing by not using for loop in matlab

t = linspace(10, 1000, 100);
for 1:n
    y(n)=1+t(n)^2;
    eq = @(x) (N + x)/(y(n) + k) + N*x*exp(-(t(n)));
end
%Say we need to find the range of values of solution of eq for all values of range
%n. N, k are constants. 
%Is it possible to implement the same without for loop

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Walter Roberson 2022-3-14

Note that you are overwriting all of eq in each iteration of the loop.

When you say "solution of eq" are you looking for the values of x such that eq(x) == 0 ?

Amy Topaz 2022-3-14

yes

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Answer 1

Walter Roberson 2022-3-14

0
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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1670859-finding-the-functionality-for-the-loop#answer_916784

在 MATLAB Online 中打开

syms t N k x

T = linspace(10, 1000, 100).';

y = 1 + t^2;

eqn = (N + x)/(y + k) + N*x*exp(-(t))

eqn =

sol_x = solve(eqn, x)

sol_x =

sols_x = subs(sol_x, t, T);

sols_x(1:5)

ans =

sols_x(end)

ans =

vpa(limit(sols_x(end), N, 1))

ans =

vpa(limit(sols_x(end), N, inf))

ans =

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Walter Roberson 2022-3-14

Note that if you are not using the symbolic toolbox, then the exp(1000) that shows up in the last entry, will almost certainly overflow double precision to give you infinity at that point.

Amy Topaz 2022-3-14