Error using a for-loop
显示 更早的评论
The following gives an error and I don't know why. The code runs perfectly when I leave '(i_testen)' away behind 'Enkel_hoek_afg'.
for i_testen=1:5
...
Enkel_hoek_afg(i_testen) = Enkel_hoek(1:Afg_c_RANK_RKNE(2,1))
end
Error: In an assignment A(I) = B, the number of elements in B and I must be the same.
采纳的回答
Star Strider
2014-12-19
See if this solves it:
for i_testen=1:5
...
Enkel_hoek_afg(i_testen,:) = Enkel_hoek(1:Afg_c_RANK_RKNE(2,1))
end
This assumes ‘Enkel_hoek(1:Afg_c_RANK_RKNE(2,1))’ is a row vector of constant length.
If it is not, create a cell array instead:
Enkel_hoek_afg{i_testen} = Enkel_hoek(1:Afg_c_RANK_RKNE(2,1))
Note that here, curly brackets ‘{}’ replace parentheses ‘()’ on the left-hand side of this assignment.
6 个评论
Sam
2014-12-19
Star Strider
2014-12-19
Does it throw an error for the cell array? It shouldn’t.
If it throws an error for the first option:
Enkel_hoek_afg(i_testen,:) = Enkel_hoek(1:Afg_c_RANK_RKNE(2,1))
what are the row and column sizes of ‘Enkel_hoek’?
What is the value stored in ‘Afg_c_RANK_RKNE(2,1)’ when it throws the error?
Star Strider
2014-12-19
If the length changes with each iteration, use my cell array solution instead:
Enkel_hoek_afg{i_testen} = Enkel_hoek(1:Afg_c_RANK_RKNE(2,1))
Note that here, curly brackets ‘{}’ replace parentheses ‘()’ on the left-hand side of this assignment.
Sam
2014-12-20
Star Strider
2014-12-20
My pleasure!
更多回答（0 个）
类别
在 帮助中心 和 File Exchange 中查找有关 Data Type Identification 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Translated by 
