Error using a for-loop

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Sam
Sam 2014-12-19
评论: Star Strider 2014-12-20
The following gives an error and I don't know why. The code runs perfectly when I leave '(i_testen)' away behind 'Enkel_hoek_afg'.
for i_testen=1:5
...
Enkel_hoek_afg(i_testen) = Enkel_hoek(1:Afg_c_RANK_RKNE(2,1))
end
Error: In an assignment A(I) = B, the number of elements in B and I must be the same.

采纳的回答

Star Strider
Star Strider 2014-12-19
See if this solves it:
for i_testen=1:5
...
Enkel_hoek_afg(i_testen,:) = Enkel_hoek(1:Afg_c_RANK_RKNE(2,1))
end
This assumes ‘Enkel_hoek(1:Afg_c_RANK_RKNE(2,1))’ is a row vector of constant length.
If it is not, create a cell array instead:
Enkel_hoek_afg{i_testen} = Enkel_hoek(1:Afg_c_RANK_RKNE(2,1))
Note that here, curly brackets ‘{}’ replace parentheses ‘()’ on the left-hand side of this assignment.
  6 个评论
Sam
Sam 2014-12-20
Strange, when I tried it the first time it didn't work. Now I've tried it again, and it works... Well, thanks a lot!

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