Doubt in matlab coding

2022 3 17
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更新时间：2022 3 29
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I want to get the output of this concept:
that is, if Eg>Egm
then output is Ns =5,6,7
Otherwise if Eg<Egm
output as Nb=1,2,3
else Nsb=4
I want to get corresponding N values for each condition.How to get this?
a=3;b=8;
Eg=[50 100 150 175 200 250 300];
Egm=Mean(Eg);
P=[20 15 10 5 1 0.5 0.1]
for N=1:1:7
if Eg>Egm
% output as Ns
elseif Eg<Egm
% output as Nb
else
%output as Nsb
end
end
Based on this values,I want to compute following
Xs=(P(n)/a)-1;But value of P(n) is taken ony the value corresponding to Ns,that is 1,0.5,0.1
Xb=(P(n)/b)-1;But value of P(n) is taken ony the value corresponding to Nb,that is 20,15,10
Xsb=Eg; For the value Nsb
How this concept can be coded?

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 采纳的回答

Mathieu NOE
Mathieu NOE 2022-3-17

1 个投票

hello
here you are my friend, without a for loop
a=3;b=8;
Eg=[50 100 150 175 200 250 300];
Egm=mean(Eg);
P=[20 15 10 5 1 0.5 0.1];
m = length(Eg);
Ns = find(Eg>Egm);
Nb = find(Eg<Egm);
Nsb = (1:m);
Nsb(Ns) = [];
Nsb(Nb) = [];
Xs=(P(Ns)/a)-1;
Xb=(P(Nb)/b)-1;
Xsb=Eg(Nsb);

12 个评论
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Ancy S G
Ancy S G 2022-3-17
Ok sir.Its good and thank you.But I wanted to know how this concept go throuh a 'for loop'.Is this concept possible with for loop?
Mathieu NOE
Mathieu NOE 2022-3-17
sure
a=3;b=8;
Eg=[50 100 150 175 200 250 300];
Egm=mean(Eg);
P=[20 15 10 5 1 0.5 0.1];
Ns = [];
Nb = [];
Nsb = [];
for ci=1:length(Eg)
if Eg(ci)>Egm
% output as Ns
Ns = [Ns ci];
elseif Eg(ci)<Egm
% output as Nb
Nb = [Nb ci];
else
%output as Nsb
Nsb = [Nsb ci];
end
end
Xs=(P(Ns)/a)-1;
Xb=(P(Nb)/b)-1;
Xsb=Eg(Nsb);
Ancy S G
Ancy S G 2022-3-17
Thank you so much sir.Its so helpful.
Mathieu NOE
Mathieu NOE 2022-3-17
my pleasure !
would you mind accepting my answer ?
tx
Ancy S G
Ancy S G 2022-3-25
Sir,I have also want to compute these equations based on the above concept.Would you please answer this,how to code this equation?
Es=∑_(ci∊Ns)(〖〖Eg〗^ci - Xs〗)
Eb=∑_(ci∊Nb)(〖Xb -〖Eg〗^ci〗)
Mathieu NOE
Mathieu NOE 2022-3-25
hello
hope I read correctly the equations - here added at the previous code :
a=3;b=8;
Eg=[50 100 150 175 200 250 300];
Egm=mean(Eg);
P=[20 15 10 5 1 0.5 0.1];
Ns = [];
Nb = [];
Nsb = [];
for ci=1:length(Eg)
if Eg(ci)>Egm
% output as Ns
Ns = [Ns ci];
elseif Eg(ci)<Egm
% output as Nb
Nb = [Nb ci];
else
%output as Nsb
Nsb = [Nsb ci];
end
end
Xs=(P(Ns)/a)-1;
Xb=(P(Nb)/b)-1;
Xsb=Eg(Nsb);
%% Es
Es = 0;
for k = 1:numel(Ns)
ci = Ns(k);
Es = Es + (Eg(ci).^ci - Xs(k));
end
Es
%% Eb
Eb = 0;
for k = 1:numel(Nb)
ci = Nb(k);
Eb = Eb + (Xb(k) - Eg(ci).^ci);
end
Eb
Ancy S G
Ancy S G 2022-3-28
thank you
Mathieu NOE
Mathieu NOE 2022-3-28
my pleasure !
Ancy S G
Ancy S G 2022-3-29
Sir,I have one more doubt.I have to check a condition using while loop.
that is,
If X(k+1)-X(k)<=0.01 is true
then terminate
else continue
where k is the no of iterations.
a=3;b=8;
Eg=[50 100 150 175 200 250 300];
Egm=mean(Eg);
P=[20 15 10 5 1 0.5 0.1];
m = length(Eg);
Ns = find(Eg>Egm);
Nb = find(Eg<Egm);
Nsb = (1:m);
Nsb(Ns) = [];
Nsb(Nb) = [];
X=(P(Ns)/a)-1;
X=(P(Nb)/b)-1;
X=Eg(Nsb);
I want to get each iterative value.Would you please answer this?
Mathieu NOE
Mathieu NOE 2022-3-29
hello
sure , no problem ,
this would be the code , but it's not clear to me what iterative computation you want to do - does it has a connection to the previous code I sent to you ?
for k = 1:numel(X)-1
dX = X(k+1)-X(k);
if dX <=0.01
break
else
X % my computation here
end
end
Ancy S G
Ancy S G 2022-3-29
Thank you for your valuable effort.
Sir,it's the same code.
Here Xs,Xb,Xsb in the above code,I just put it as X for all.
I want to stop this iterative process until the error between previous iterative value and new value converges nearly to zero.That is the value of X in this code.
My doubt is how to make this code as a iterative computation and the know the values of X after each iteration.
Mathieu NOE
Mathieu NOE 2022-3-29
hello again
I am not sure to understand how you want to have the X by iteration
the previous code (see below) is based on conditional statements (if, else,...) and I don't see how you can replace that logic with an iteration on X
maybe you can help me clarify this point
a=3;b=8;
Eg=[50 100 150 175 200 250 300];
Egm=mean(Eg);
P=[20 15 10 5 1 0.5 0.1];
Ns = [];
Nb = [];
Nsb = [];
for ci=1:length(Eg)
if Eg(ci)>Egm
% output as Ns
Ns = [Ns ci];
elseif Eg(ci)<Egm
% output as Nb
Nb = [Nb ci];
else
%output as Nsb
Nsb = [Nsb ci];
end
end
Xs=(P(Ns)/a)-1;
Xb=(P(Nb)/b)-1;
Xsb=Eg(Nsb);

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