how to count array of 1 and 0 repeated times
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I am tryig to make a counter that will look at a set of data that consists of ones and zeros and count how many times the number 1 is repeated 10 times consecutively and count that occurence as a 1 and any other occurence of a zero or less than 10 times as a zero.
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David Hill
2022-3-17
a=ones(1,10);
b=[];
for k=1:10
b=[b,randi(2,1,20)-1,a];
end
% above just generates binary series
s=num2str(b);
s=s(s~=' ');
count=length(regexp(s,'[1]{10,}'));
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Matt J
2022-3-17
编辑:Matt J
2022-3-17
Using,
[~,~,runlengths]=groupLims(groupTrue(data==1),1);
count= nnz(runlengths>=10)
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Image Analyst
2022-3-18
I gave an example below where I prove it worked. If it doesn't work for your vector, attach your vector in a text or mat file.
Image Analyst
2022-3-18
编辑:Image Analyst
2022-3-18
If you have the Image Processing Toolbox, you can use the built-in bwlabel and do it in one line of code. If m is your matrix:
[~, count] = bwlabel(bwareafilt(logical(m), [10, inf]))
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Image Analyst
2022-3-18
Here is an example
m = zeros(1, 1000);
% Make 3 stretches of 10 or more:
m(100:110) = 1;
m(330:380) = 1;
m(560:590) = 1;
[~, count] = bwlabel(bwareafilt(logical(m), [10, inf]))
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