Chessboard illumination - Problems using imrotate
1 次查看(过去 30 天)
显示 更早的评论
Hello! I'm doing a chessboard with dimensions of 512x512. In my code I should apply a parameter which makes the illumination of the chessboard varies given an angle (MCangle). I used the imrotate function, but the output image shows the chessboard with black corners. I wanted that my rotate image fill my original image. I've tried to use imrotate without the 'crop' parameter, but it shows an error saying "Matrix dimensions must agree.", as expected. Can someone help me with this problem? I would be very thankful!! And sorry if my english is bad.
f1=255*ones(64);
f2=zeros(64);
R1=[f1 f2 f1 f2 f1 f2 f1 f2];
R2=[f2 f1 f2 f1 f2 f1 f2 f1];
chess=[R1;R2;R1;R2;R1;R2;R1;R2];
vl=1:512;
vc=ones(512,1);
MA=vc*vl;
MB=mat2gray(MA);
%illumination intensity
MC=MB*(0.6)+0.2;%MC=MB*(IMAX-IMIN)+IMIN;
MCangle=imrotate(MC,45,'crop');
chessintensity=chess.*MCangle;
chessI8=uint8(chessintensity);
imshow(chessI8)
4 个评论
Matt J
2022-3-17
Well, you need to edit your post to describe what the actual problem is. Currently, you describe a "matrix dimensions must agree" problem that doesn't exist.
采纳的回答
Matt J
2022-3-17
编辑:Matt J
2022-3-17
f1=255*ones(64);
f2=zeros(64);
R1=[f1 f2 f1 f2 f1 f2 f1 f2];
R2=[f2 f1 f2 f1 f2 f1 f2 f1];
chess=[R1;R2;R1;R2;R1;R2;R1;R2];
[x,y]=ndgrid((1:512)-mean(1:512));
MB=rescale(-x*sind(45)+y*cosd(45),0,1);
%illumination intensity
MCangle=MB*(0.6)+0.2;%MC=MB*(IMAX-IMIN)+IMIN;
chessintensity=chess.*MCangle;
chessI8=uint8(chessintensity);
imshow(chessI8)
2 个评论
更多回答(0 个)
另请参阅
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!