To select the indices of logical "1" in first 2D matrix, and then replace those corresponding indices in second 2D matrix with logical "0"

3 次查看(过去 30 天)
Dear Researchers and Programmers,
I have 2D matirx with logical 1, and 0. I need to select the indices having logical value 1.
Then in the second matrix, I want to replace those indices with zero.
I have attached both the matrices one is binary image and other is processed image.
I look forward to receive your valueable suggestions.
Many thanks.

采纳的回答

Cris LaPierre
Cris LaPierre 2022-3-18
Use logical indexing (Ch 11 of MATLAB Onramp)
A = randi([0 3],5)
A = 5×5
1 0 1 1 2 0 3 1 2 3 3 3 1 2 2 0 1 0 2 0 2 1 0 0 3
B = rand(5);
B(A==1) = 0
B = 5×5
0 0.5810 0 0 0.1176 0.7124 0.2019 0 0.8901 0.0881 0.5986 0.7831 0 0.6246 0.6896 0.2216 0 0.0883 0.1362 0.5453 0.9653 0 0.8447 0.6397 0.7059
  3 个评论
Cris LaPierre
Cris LaPierre 2022-3-18
If you are getting a logical output, you have not done what I showed. In my example, B is an array of doubles, not logicals. You use a logical array to perform the indexing (A==1). The assumption is that A and B are the same size.

请先登录,再进行评论。

更多回答(0 个)

产品


版本

R2022a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by