How to escape a portion of a string in regular expressions

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Max Heimann 2022-3-21

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https://ww2.mathworks.cn/matlabcentral/answers/1676459-how-to-escape-a-portion-of-a-string-in-regular-expressions

评论： Max Heimann 2022-3-21

采纳的回答： Walter Roberson

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Hello,

i want to dynamically create a regular expression from an input string. However i only want a small subset of expressions to be treated as such. Most of the input shall be treated as literal (e.g. dots '.' shall actually be treated as dots and not wildcards)

Is there a way to escape a whole group/substring when defining a regexp, or is the only way to escape all special chars, except the ones i want to keep, manually. If i need to escape everything manually, is there a syntax/keyword which gets me all special chars in the string so i can escape all of them?

Example (dots shall be treated as literal dots):

>> r = myfun('a.b.c','a.b.')
r = 1
>> r_myfun('aXb.c','a.b.')
r = []

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Walter Roberson 2022-3-21

Perhaps the newer "pattern" facilities would help?

Max Heimann 2022-3-21

Thats also great, but i need it to work in an earlier version than 2020.

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采纳的回答

Walter Roberson 2022-3-21

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https://ww2.mathworks.cn/matlabcentral/answers/1676459-how-to-escape-a-portion-of-a-string-in-regular-expressions#answer_923009

https://www.mathworks.com/help/matlab/ref/regexptranslate.html

regexptranslate with the 'wildcard' option, perhaps?

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Max Heimann 2022-3-21

This is great, thank you. I think i can work with this and use the 'escape' option. Afterwards i can look for the escaped versions of the patterns i want to match and de-escape them.

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