Extracting single numbers from each cell in a cell array

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I have a 451x1 cell array, each cell is a 57x41 double. From each cell (which represents a timepoint) I need to extract the value of one location, the same one for all cells. e.g. From all 451 cells I need to extract (32, 25) from the 57x41 double. I then need to combine these into a 451x1 double. How can I do this? I'm having trouble getting the correct notation.
Thank you

采纳的回答

Voss
Voss 2022-3-21
% first, create a cell array like yours:
C = cell(451,1);
for ii = 1:numel(C)
C{ii} = randn(57,41);
end
% look at the first couple of cells' (32,25) element:
C{1}(32,25)
ans = -0.4494
C{2}(32,25)
ans = -0.5907
% now get the specified element from each cell into a double array:
A = cellfun(@(x)x(32,25),C)
A = 451×1
-0.4494 -0.5907 -0.8715 -1.0468 0.4059 -0.2548 -0.2243 -0.9131 0.9573 -0.2997
  2 个评论
Guglielmo Sonnino Sorisio
Thank you,
I'm not sure where I need to substitute the name of the cell array in the code you wrote, if I run it like you wrote it I get the correct output but if I try to substitute the name of the cell array (which is u_filtered) it gives me error messages.
Voss
Voss 2022-3-21
编辑:Voss 2022-3-21
Anywhere my code uses C, your code should use u_filtered, but it's really just one line to do the actual indexing (the rest is to create my cell array, which you already have):
% get the specified element from each cell into a double array:
A = cellfun(@(x)x(32,25),u_filtered)

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