How to use nested loop to produce the row and columns like that

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Shuoze Xu
Shuoze Xu 2022-3-22
评论： Mathieu NOE 2022-3-22
Given a 2D array, called A, of size 5 x 5,
Sample Output: Given A = [2,4,8,7,3;2,2,3,4,3;5,5,4,2,7;8,2,7,3,9;1,2,3,4,5];
output:
2 4 8 7 3
2 2 3
5 5 7
8 2 7 3 9
1 2 3 4 5
% My code
A = [2,4,8,7,3;2,2,3,4,3;5,5,4,2,7;8,2,7,3,9;1,2,3,4,5];
rows = size(A,1) % the number of rows in A
columns = size(A,2) % the number of columns in A
B = [];
for row = 1:rows
for column = 1:columns
if (row == 2 || row == 3)
if (column == 3 || column == 4)
B = [B A(i)]
end
end
end
end
disp(B);
My code is wrong i thought

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采纳的回答

Mathieu NOE
Mathieu NOE 2022-3-22
hello
seems to me B is simply A but rows 2 and 3 for columns 3 and 4 are empty (filled with NaN)
code :
A = [2,4,8,7,3;2,2,3,4,3;5,5,4,2,7;8,2,7,3,9;1,2,3,4,5];
B = A;
B(2:3,3:4) = NaN;
results :
A =
2 4 8 7 3
2 2 3 4 3
5 5 4 2 7
8 2 7 3 9
1 2 3 4 5
B =
2 4 8 7 3
2 2 NaN NaN 3
5 5 NaN NaN 7
8 2 7 3 9
1 2 3 4 5
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更多回答（1 个）

Arif Hoq
Arif Hoq 2022-3-22
Ran in:
you did not clear your expection. you can try this
A = [2,4,8,7,3;2,2,3,4,3;5,5,4,2,7;8,2,7,3,9;1,2,3,4,5];
rows = size(A,1); % the number of rows in A
columns = size(A,2); % the number of columns in A
B = [];
for row = 1:rows
for column = 1:columns
% if row == 2 || row == 3 && column == 3 || column == 4
if (row == 2 || row == 3)
if (column == 3 || column == 4)
B = [B A(row)]
end
end
end
end
B = 2
B = 1×2
2 2
B = 1×3
2 2 5
B = 1×4
2 2 5 5
disp(B);
2 2 5 5
  2 个评论
Shuoze Xu
Shuoze Xu 2022-3-22
My expectation is to remove the elements in the third and fourth columns of the second row, and the third and fourth columns of the third row and print the array.

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