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reallocating matrix concatenated as string

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Berfin Çetinkaya
Berfin Çetinkaya 2022-3-24
评论： Berfin Çetinkaya 2022-3-24
birlestirbirincifaz = cell(20,69) ;
for i = 1:20
for j = 1:69
birlestirbirincifaz{i,j} = [num2str(sonucmatrisi(i,j)),'-',num2str(faz1atananmakineler(i,j))] ;
end
end
I combined two matrices as strings using this code.
But now I have to take it apart again. What should I do?
(small snippet of my matrix)
'10-10' '22-22' '42-42'
'193.92-8' '68.8-7' '9.34-1'
'193.92-8' '68.8-8' '9.34-3'

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采纳的回答

Stephen23
Stephen23 2022-3-24
编辑：Stephen23 2022-3-24
Ran in:
Much better to use string arrays:
M1 = [10,22,42;193.92,68.8,9.34;193.92,68.8,9.34]
M1 = 3×3
10.0000 22.0000 42.0000 193.9200 68.8000 9.3400 193.9200 68.8000 9.3400
M2 = [10,22,42;8,7,1;8,7,1]
M2 = 3×3
10 22 42 8 7 1 8 7 1
S = M1+"-"+M2
S = 3×3 string array
"10-10" "22-22" "42-42" "193.92-8" "68.8-7" "9.34-1" "193.92-8" "68.8-7" "9.34-1"
T = split(S,'-')
T = 3×3×2 string array
T(:,:,1) = "10" "22" "42" "193.92" "68.8" "9.34" "193.92" "68.8" "9.34" T(:,:,2) = "10" "22" "42" "8" "7" "1" "8" "7" "1"
str2double(T(:,:,1))
ans = 3×3
10.0000 22.0000 42.0000 193.9200 68.8000 9.3400 193.9200 68.8000 9.3400
str2double(T(:,:,2))
ans = 3×3
10 22 42 8 7 1 8 7 1
  2 个评论
Steven Lord
Steven Lord 2022-3-24
Ran in:
With a string array containing the text representations of numbers you don't need to use str2double. Just calling double is sufficient.
M1 = [10,22,42;193.92,68.8,9.34;193.92,68.8,9.34];
M2 = [10,22,42;8,7,1;8,7,1];
S = M1+"-"+M2;
T = split(S,'-');
M1After = double(T(:,:,1))
M1After = 3×3
10.0000 22.0000 42.0000 193.9200 68.8000 9.3400 193.9200 68.8000 9.3400
M2After = double(T(:,:,2))
M2After = 3×3
10 22 42 8 7 1 8 7 1

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更多回答（1 个）

Riccardo Scorretti
Riccardo Scorretti 2022-3-24
If I understand well your question, you wish to do this:
sonucmatrisi = zeros(20, 69);
faz1atananmakineler = zeros(20, 69);
for i = 1:20
for j = 1:69
tmp = sscanf(birlestirbirincifaz{i,j}, '%f-%f');
sonucmatrisi(i,j) = tmp(1);
faz1atananmakineler(i,j) = tmp(2);
end
end

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