Sort vector A according to vector B

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Aru E
Aru E 2022-3-27
回答： Bruno Luong 2022-3-27
I have two 14x1 vectors A and B. i am trying to sort A to match with B.
A = [0.9; 0.2; 0.4; 0.2; 0.3; 0.4; 0.7; 0.4; 0.1; 0.8; 0; 0; 0; 0];
B = [0; 0; 1; 1; 1; 1; 0; 0; 0; 0; 0; 0; 0; 0];
I am trying to make it so the 0's in A match with the 1's in B with a result of:
C = [0.9; 0.2; 0; 0; 0; 0; 0.4; 0.2; 0.3; 0.4; 0.7; 0.4; 0.1; 0.8]
This is my attempt:
TF1 = B(:,1)==1;
for j = 1:length(A)
n = j:length(B);
A(TF1,:) = 0
end
Any help would be appreciated. Thank you!
  2 个评论
Image Analyst
Image Analyst 2022-3-27
编辑：Image Analyst 2022-3-27
Why? What's the use case (context, reason)? Is it homework?
How do I get help on homework questions on MATLAB Answers? - MATLAB Answers - MATLAB Central
Did you try a simple for loop with two counters to keep track of indexes?
Aru E
Aru E 2022-3-27
I am creating a program to automate a 2D truss solution. To solve for my reaction forces I need my displacement vector (A) to have the zeros lined up with my boundary conditions (B). I have not been able to successfully do this with a for loop or by sorting the vectors.

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采纳的回答

Bruno Luong
Bruno Luong 2022-3-27
Ran in:
A = [0.9; 0.2; 0.4; 0.2; 0.3; 0.4; 0.7; 0.4; 0.1; 0.8; 0; 0; 0; 0];
B = [0; 0; 1; 1; 1; 1; 0; 0; 0; 0; 0; 0; 0; 0];
Ais0=A==0;
Bis1=B==1;
C=zeros(size(A));
C(Bis1)=A(Ais0);
C(~Bis1)=A(~Ais0);
C
C = 14×1
0.9000 0.2000 0 0 0 0 0.4000 0.2000 0.3000 0.4000

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