Movmean skipping NaN in array

3 次查看（过去 30 天）
sr9497
sr9497 2022-3-27
评论： sr9497 2022-3-28
Ran in:
I have an array
x = [20 10 5 NaN]; %and I now use:
movmean([x; x(1, :)], [0 1], 1, 'omitnan', 'Endpoints', 'discard')
ans = 1×4
20 10 5 NaN
to calculate the mean, [15 7.5 5 20].
I would like to get [15 7.5 12.5 NaN] so skip over NaN and calculate the mean of 20 and 5 as well, instead of having NaN being replaced by 20 after using movmean. What is the best way to do this?
  2 个评论
Adam Danz
Adam Danz 2022-3-27
I think you meant to transpose x. It needs to be a column vector in your example.
Adam Danz
Adam Danz 2022-3-27
> I would like to get [15 7.5 12.5 NaN]
Where does the last NaN come from?
What would be the expected value for this: [10 20 NaN 5 NaN NaN 10 20] ?

请先登录，再进行评论。

请先登录，再回答此问题。

回答（1 个）

Image Analyst
Image Analyst 2022-3-27
Ran in:
Not sure where the 12.5 is coming from but maybe you'd like this:
x = [20, 10, 5, NaN];
kernel = [1,1];
xs = x;
xs(isnan(x)) = 0;
theSum = conv(xs, kernel, 'same')
theSum = 1×4
30 15 5 0
theCount = conv(~isnan(x), kernel, 'same')
theCount = 1×4
2 2 1 0
output = theSum ./ theCount
output = 1×4
15.0000 7.5000 5.0000 NaN
  5 个评论
显示 3更早的评论
Image Analyst
Image Analyst 2022-3-28
So now I'm getting confused. Do you have a row vector, or a 2-D matrix? You've shown both.
sr9497
sr9497 2022-3-28
A 2-D matrix, the row vector was a mistake.

请先登录，再进行评论。

类别

在 Help Center 和 File Exchange 中查找有关 Matrices and Arrays 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by