how do xor to cell array1*1?
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X=
1×1 cell array
{'10000000'}
Y=
1×1 cell array
{'01000000'}
Z=xor(X,Y)
Z={'11000000'}
采纳的回答
Here's one way:
% binary as cellchar
X = {'10000000'};
Y = {'01000000'};
% convert to actual logical arrays
X = X{:}=='1';
Y = Y{:}=='1';
% do a thing
Z = xor(X,Y)
% convert back to cellchar i guess
map = '01';
Z = {map(Z+1)}
If you expect the answer you show, use
Z = ~xor(X,Y)
instead for XNOR
更多回答（1 个）
Try this:
X = {'10000000'};
Y = {'01000000'};
Z = bitxor(bin2dec(X{1}), bin2dec(Y{1})) % A decimal number.
% Convert to binary digits.
Z = dec2bin(Z) % Correct
% Poster say the answer should be:
Z={'00111111'} % ? Huh?
I'm not sure you understand the concept of XOR. It's one, or the other, but not both. So where both bits match up the output is zero and where they are different it's one.
You can put Z into a cell if you want
Z = {dec2bin(Z)}
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