How to use sprintf in a variable name?
显示 更早的评论
For example, I want to do this (but it gives an error):
row = 4
col = 2
Duration_Trial(num2str('col'))_pp(num2str('row')) = length(data_stair_rise(row, col).VideoSignals)/data_stair_rise(row, col).VideoFrameRate; % expression after the '=' is not important.
What did I do wrong?
回答(1 个)
Star Strider
2014-12-27
You don’t need num2str. Just use ‘row’ and ‘col’ as they are:
Duration_Trial(col, _pp(row)) = length(data_stair_rise(row, col).VideoSignals)/data_stair_rise(row, col).VideoFrameRate;
I cannot follow what you are doing, but that change should at least get you closer to what you want.
类别
在 帮助中心 和 File Exchange 中查找有关 Data Type Identification 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!