Error when storing data after forloop

1 次查看（过去 30 天）

显示更早的评论

Sam 2014-12-27

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/168267-error-when-storing-data-after-forloop

关闭： MATLAB Answer Bot 2021-8-20

在 MATLAB Online 中打开

I want to calculate the derivative of RHEE. I also created 2 for loops. I want to store each derivative for each test. But it gives the following error : ()-indexing must appear last in an index expression.

aantal_proefpersonen = length(data_stair_rise);
for welke_pp=1:aantal_proefpersonen %forloop for 5 subjects
  switch welke_pp
      case 1
      case 2
      case 3
      case 4
      case 5
  end
for i_testen=1:length(data_stair_rise) %forloop for all measurements per subject
 RHEE = data_stair_rise(welke_pp,i_testen).VideoSignals(:, strcmp('RHEE', data_stair_rise(welke_pp,i_testen).VideoSignals_headers)); %data extraction
      RHEE = d.RHEE;
      T  = 0:size(RHEE)-1;
      dRHEE(welke_pp,i_testen) = gradient(welke_pp,i_testen)(RHEE,T); %want to store each derivative (error)

end end

6 个评论
显示 4更早的评论隐藏 4更早的评论

Geoff Hayes 2014-12-28

编辑：Geoff Hayes 2014-12-28

Sam - since there is no code for any of your cases, then there is no need for it, so you may as well remove it. Please see Per's links to the details of switch.

Also, please answer my previous questions concerning your use of gradient.

Image Analyst 2014-12-28

I'm just so lost with all the non-English words and bad formatting that I'm not even attempting to understand what's going on there. It's too confusing. Sorry. Plus it looks a lot like your other questions so I don't know what's different here as compared to all the other questions. Good luck though.

http://www.mathworks.com/matlabcentral/answers/13205-tutorial-how-to-format-your-question-with-markup

此问题已关闭。

回答（0 个）

此问题已关闭。

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by