Brute force for finding optimal value

5 次查看(过去 30 天)
I have a function Say, f(x)=(1-0.5)*[(sin(x-0.25))/2]+0.5.
and x lie in range [-pi,pi], which need to be optimized such that the f(x) will be maximum. The final result f(x), after applying brute force, will be of order 1*10. How to incorporate it, using brute force?
Regards and thanks in anticipation.
  2 个评论
Chetan Fadnis
Chetan Fadnis 2022-3-28
Sorry, I have updated.
I need 10 different values of x, so that finally I can get a vector of 1*10.

请先登录,再进行评论。

采纳的回答

Walter Roberson
Walter Roberson 2022-3-28
Brute force is defined as trying all possible values. You have about 8*10^18 representable values in that range, so if you need to use brute force then the best you can hope for is roughly 3 months of computation (unless a gpu could be used)
  1 个评论
Walter Roberson
Walter Roberson 2022-3-28
There might be reason to divide a range into segment, and run fmincon() of the function confined to that segment, and the gather all of the results together. But that would not be considered brute force.

请先登录,再进行评论。

更多回答(1 个)

Torsten
Torsten 2022-3-28
编辑:Torsten 2022-3-28
I don't understand. Your function has a single maximum at x=0.25+pi/2. Why are you talking about 10 x-values ?
Do you perhaps mean
f = @(x)(1-0.5)*sin(x-0.25)/2 + 0.5;
x = linspace(-pi,pi,10); % Choose 10 equidistant x-values
[imax,fmax] = max(f(x)); % find maximum and position under the 10 x-values
xmax = x(imax) % print out x position of maximum

类别

Help CenterFile Exchange 中查找有关 Assembly 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by