Non-linear loads

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Mohammed Yakoob
Mohammed Yakoob 2022-3-30
回答： Mohammed Yakoob 2022-4-4
I want to implement these loads as nonlinear and harmonic by using codes or Simulink to deal with this problem in control system?

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采纳的回答

Dr. Pemendra Kumar Pardhi
Hello Mohammed Yakoob,
For above you need to use MATLAB Simulink, in Simulink you can devoloped model as atteched picture file.
Thanks
Pemendra Pardhi

更多回答（4 个）

Mohammed Yakoob
Mohammed Yakoob 2022-3-30
Hello dear and thanks so much for your answer!! I agree with your answer but I want the way that implemented this loads as a model to deal with them in control system not as the simscap electrical!!
  1 个评论
Dr. Pemendra Kumar Pardhi
Dr. Pemendra Kumar Pardhi 2022-3-31
In simscape electrical, control can also be implements,
For what you want, can you share paper (if it is possible)?

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Mohammed Yakoob
Mohammed Yakoob 2022-4-1
Yes dear friend I attached the article that I want to simulate
  1 个评论
Mohammed Yakoob
Mohammed Yakoob 2022-4-1
But my problem with the disturbance term as implents in this article as different loads

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Mohammed Yakoob
Mohammed Yakoob 2022-4-4
Hello Dear
I tray to implement these disturebance loads if I deal correct as shown bellow but the last one is the nonlinear signal I can't get it so please if you have any information let me knw??
My codes :
clc
close all
clear
%% Plant Paramiters
f= 60;
Ts= 1/f; %% one period
Th=Ts/2; %%half period
Wo= 2*pi*f;
Vdc= 300;
C_st=15*10^-6;
L_t=2*10^-3;
R_l= 40; %resistance load
R_li=3; %resistance of the line
%% Implement a Single Phase Microgrid in a contious time form
% x_dot= AX+BU+dW ; Y= CX+DU+0W.
% X=[il Vg]' ; U=[Vsw] ; d= [ig]; Y=[Vg].
% for i= 1:1000
Aop=[0 1/L_t; 1/C_st 0];
Bop= [1/L_t; 0];
d=[0; -1/C_st];
Cop=[0 1];
Dop= [0];
B= [Bop d];
%% Imlement the system
sys=ss(Aop,B, Cop, Dop);
sys_d= c2d(sys,0.0001);
[Ad,Bd,Cd,Dd]=ssdata(sys_d);
%% Performance of The Open Loop System
t = 0.000:0.0001:Th;
V_r =Vdc*sin(Wo* t);
%% Cotrollability of the system
Co= ctrb(sys);
rank(Co);
%% LQR_LMI
Ac=Aop;
Bc= Bop;
C= Cop;
nx = size(Ac,2);
nu = size(Bc,2);
% closed loop
% LQR weights
Q = diag([1 1e-5]);
R = 1;
Klqr = lqr(Ac,Bop,Q,R,[]);
% % % LMI
% % A=Ac;
% % B1 = eye(nx);
% % B2=Bc;
% %
% % C1 = eye(nx);
% % D11 = zeros(nx,nx);
% % D12 = zeros(nx,nu);
% %
% % C2 = [sqrt(Q);
% % zeros(nu,nx)];
% % D21 = zeros(nx+nu,nx);
% % D22 = [zeros(nx,nu);
% % sqrt(R)];
% %
% % Pp = ltisys(A, [B1 B2], [C1; C2], [D11 D12; D21 D22]);
% %
% % siz = size(D22);
% % gamma0 = 0;
% % obj = [gamma0 0 0 1];
% %
% % [gopt,h2opt,Klmi,Pcl,X] = msfsyn(Pp,siz,obj);
% %
% % Klqr
% % Klmi
%% Closed loop system
Acl= [Aop-(Bop*Klqr)];
Bcl= [B];
Ccl= [0 1];
Dcl= [0 0];
states = {'i_L' 'V_g'};
inputs1 = {'V_r' 'dis'};
outputs1 = {'V_g'};
poles= eig(Acl);
sys_cl = ss(Acl,Bcl,Ccl,Dcl,'statename',states,'inputname',inputs1,'outputname',outputs1);
%% At the disturebance eqaul to zero
input1 = [V_r; zeros(size(t))]; %%assume tha the disturebance =0.
[y1,t,x]=lsim(sys_cl,input1,t);
figure()
plot(t,y1)
ylabel('V_out')
xlabel('time')
title('LQR controller Without the Disterbance Term')
grid on
%% LQR when the system has a load term at R=40 Ohm
dis = (V_r/R_l+R_li);
input2 = [V_r' dis'.*0.01];
[y2,t,x]=lsim(sys_cl,input2,t);
figure()
plot(t,y2)
ylabel('V_out')
xlabel('time')
title('LQR controller With the Disterbance Term at R=40Ohm')
grid on
%% 1) PERFORMANCE AGAINST UNKNOWN LOAD
z1=complex(0,-Wo*62.86e-6);
z2= complex(0.35,Wo*223.8e-3);
z3= complex(228);
z4=complex(76,-Wo*10e-6);
z5=complex(152,Wo*111.9e-3);
Z11= (1/z1)+ (1/z2) +(1/z3);
Z22=(1/z4)+(1/z5);
n= numel(t);
% % for m= 1:n
% %
% % if m<= 36
% % dis11= (y1(m,1)/R_li+Z11)';
% % dis11(1,m)=dis11;
% % elseif m<=n-36
% %
% % dis12= (y1(36+m,1)/R_li+Z11+Z22)';
% % dis12(1,m)=dis12;
% %
% % end
% %
% % end
% dis1=[dis11 dis12];
for m= 1:n
if m<= 36
dis11= 1e-1*[cos(5*2*pi*m')+cos(1*2*pi*m')+cos(.1*2*pi*m')];
dis11(1,m)=dis11;
elseif m<=n-36
dis12= 1*[cos(4*2*pi*m')+cos(2*2*pi*m')+cos(.2*2*pi*m')];
dis12(1,m)=dis12;
end
end
dis1=[dis11 dis12];
input3 = [V_r' dis1'];
[y3,t,x]=lsim(sys_cl,input3,t);
figure()
plot(t,y3)
ylabel('V_out')
xlabel('time')
title('PERFORMANCE AGAINST UNKNOWN LOAD')
grid on
%% (2) PERFORMANCE AGAINST HARMONIC LOAD
dis = ((V_r/R_l+R_li)+7*sin(Wo*t'));
input3 = [V_r' dis'.*0.001];
[y3,t,x]=lsim(sys_cl,input3,t);
figure()
plot(t,y3)
ylabel('V_out')
xlabel('time')
title('PERFORMANCE AGAINST HARMONIC LOAD')
grid on
Mohammed Yakoob
Mohammed Yakoob 2022-4-4
if you ask me, why dont use the simscape electrical, because I dont know the why how to connect these loads to my control simulink with the output of my system (Y) or as reterun disturebance as input??

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